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shtirl [24]
3 years ago
10

Verify the trig identity: tan^2 theta + cot^2 theta / csc^2 theta = sec^2 theta

Mathematics
1 answer:
Mars2501 [29]3 years ago
3 0

Answer:

See proof below

Step-by-step explanation:

In trigonometry identity

tan^2 theta = sin^2 theta /cos^2 theta

cot^2 theta = cos^2 theta/sin^2 theta

csc^2 theta = 1/sin^2 theta

Substitute into the expression

(sin^2 theta /cos^2 theta )+ (cos^2 theta/sin^2 theta)/1/sin^2 theta

= [sin^4theta + cos^4theta/cos^2 theta sin^2 theta]÷(1/sin^2 theta)

= 1/cos^2 theta sin^2 theta÷(1/sin^2 theta)

= 1/cos^2 theta sin^2 theta * sin^2 theta/1

= 1/cos^2theta

= sec^2theta (Proved!)

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Name three solutions to the inequality. x<7
Gnom [1K]

Answer:

x=anything less than 7

x=5

x=-2

x=-7

x= anything less than 7

Step-by-step explanation:

7 0
3 years ago
Yea someone explain/solve this...
xenn [34]

           \rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

      <em>[refer to attachment for question ~]</em>

<em />

<em />\rule{50}{1}\large\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

First of all, We need to multiply by the denominator (10) on both sides:-

\longmapsto\sf{\displaystyle\frac{-x+8}{10} \times10=-7\times10}

On the left-hand side, the 10s cancel as follows:-

\longmapsto\sf{-x+8=-7\times10}

On the right-hand side, we multiply -7 times 10:-

\longmapsto\sf{-x+8=-70}

Subtract 8 on both sides:-

\longmapsto\sf{-x=-70-8}

We get

  \longmapsto\sf{-x=-78}

And finally, Divide by -1 on both sides:-

\longmapsto\sf{x=78}

<h3>Good luck with your studies.</h3>

\rule{300}{1}

6 0
3 years ago
Read 2 more answers
Sequence: 49, 36, 25, 16, 8, 4, 1 * Is this a arithmetic or geometric sequence? and if it is arithmetic find the common differen
timurjin [86]

Answer:

Step-by-step explanation:

The sequence is nor properly written. This is correct sequence

49, 36, 25, 16, 9, 4, 1...

Merely looking at the sequence, we can see that it doesn't form an arithmetic sequence nor does it form a geometric sequence.

The values of the sequence are all perfect squares.

Rewriting the sequence;

7², 6², 5², 4², 3², 2², 1²...

Now we can see that the base values for an arithmetic sequence as shown:

7, 6, 5, 4, 3, 2, 1...

We find the common difference of this sequence as shown

d = T2-T1 = T3-T2 = T4-T3

Given T1 = 7, T2 = 6, T3 = 5, T4 = 4

Substitute

d = 6-7 = 5-6 = 4-5 = -1

d = -1

Get the nth term using the sequence

Tn = a+(n-1)d

a is the first term

d is the common difference

n is number of terms

Tn = 7+(n-1)(-1)

Tn = 7+(-n+1)

Tn = 7+1-n

Tn = 8-n

Since their power are constant i.e squared, hence we will square the ntj term as well to get the nth term of the original sequence as;

Tn = (8-n)²

To conclude, we can say that the sequence is neither arithmetic nor geometric sequence since the terms of the sequence are prefect squares.

3 0
3 years ago
Someone please help me will give BRAILIEST !!!!!!!!!!!
andreyandreev [35.5K]
1292 this shows how many people are on the team and also how many different rotations can be allowed

7 0
3 years ago
1/5k + 15 factor out the coefficient!
skelet666 [1.2K]
1/5k+ 15
= 1/5k+ 15* (5/5) (because 5/5= 1)
= 1/5k+ (15*5)/ 5
= 1/5k+ 75/5
= 1/5k+ 75* (1/5)
= 1/5(k+ 75) (distributive property)

The final answer is 1/5(k+ 75).
3 0
3 years ago
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