Remember, order of operations
exponent before multiply
so 4x^5/6=4 times x^5/6
simplify the x^5/6 first
remember
![x^\frac{m}{n}=\sqrt[n]{s^m}](https://tex.z-dn.net/?f=x%5E%5Cfrac%7Bm%7D%7Bn%7D%3D%5Csqrt%5Bn%5D%7Bs%5Em%7D)
so
![x^\frac{5}{6}=\sqrt[6]{x^5}](https://tex.z-dn.net/?f=x%5E%5Cfrac%7B5%7D%7B6%7D%3D%5Csqrt%5B6%5D%7Bx%5E5%7D)
so
![4x^\frac{5}{6}=4\sqrt[6]{x^5}](https://tex.z-dn.net/?f=4x%5E%5Cfrac%7B5%7D%7B6%7D%3D4%5Csqrt%5B6%5D%7Bx%5E5%7D)
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Ill recomment on my thing right now with the answer let me just go read up on how to do this
The answer is C.) 33% i believe. Excuse me if i'm wrong!!!!!
Answer:
Charles practiced for the relay race for D. 9 hours last week.
Step-by-step explanation:
First, I would find the ratios the ratios for converting hurdle to javelin and javelin to relay.
Hurdle : Javelin ; 5 : 1.5
Javelin : Relay ; 2.5 : 5 or 1 : 2
Next, find the factors compared to the original numbers for hurdle to javelin.
15 / 5 = 3
To find the amount of javelin time they did, multiply 1.5 by the factor we got, 3.
1.5 * 3 = 4.5
Finally, double 4.5, since Charles does twice as much relay than he does javelin.
4.5 * 2 = 9 hours
0=-16t^2 +64
0=-16(t^2 - 4)
0=-16(t-2)(t+2)
t=2 or - 2
It will take two seconds for the object to hit the ground.