Answer:
I think the answer for this question is C
The extraneous solution of startroot 4 x 41 endroot = x 5 will be A. -8.
<h3>What is an extraneous solution?</h3>
It should be noted that an extraneous solution simply means a root of a transformed equation which isn't part of the original equation.
✓4x + 41 = x + 5
Square both sides
4x + 41 = x² + 10x + 25
x² + 6x - 16
x(x + 8) - 2(x + 8) = 0
x + 8 = 0
x= 0 + 8 = 8
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They all have either a common factor, common multiple, LCF, GCF, LCM, or GCM. The G and L stand for greater and least.
The equation that matches the given table is
y = 10x + 40
Solution:
General equation of a line : y = mx + c
Let us find the equation of the table.
<u>Common differences of X: </u>
0 – 1 = 1, 1 – 2 = 1, 3 – 2 = 1, 4 – 3 = 1, 5 – 4 = 1
<u>Common differences of Y: </u>
50 – 40 = 10, 60 – 50 = 10, 70 – 60 = 10, 80 – 70 = 10, 90 – 80 = 10


m = 10
Substitute m = 10 in general equation of a line
y = 10x + c
To find the constant term, substitute x = 0 and y = 40.
40 = 10(0) + c
40 = 0 + c
40 = c
c = 40
Therefore the equation of a line is y = 10x + 40.
Hence the equation that matches the given table is y = 10x + 40.