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3 years ago

Which counterexample shows that the conjecture "All animals that can fly are birds" is false?

2 answers:

8 0

B would be incorrect as it is not a counterexample to the claim. C would be incorrect as a chipmunk is not a bird. And D would be incorrect as the claim says "All animals that can fly are birds" it doesn't say "every bird" or "all birds can fly"
So A is the logical choice and according to what Jimthompson5910 said "bats are one animal where they can fly but they aren't birds."

QveST [7]3 years ago

3 0

It seems like you forgot to post the answer choices. However, bats are one animal where they can fly but they aren't birds. So this is one counter-example to prove the claim false. Another example would be any flying insects.

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Abcdefgh is a regular octagon. M is a point on the line dh. N is a point on the line fm. The line dn and fm are perpendicular. P

Aloiza [94]

ΔFHM and ΔDFP by addition to ΔMOF and ΔPDO respectively gives

ΔHOP and ΔDOF, which are congruent.

Response:

ΔFHM ≅ ΔDFP by transitive property of equality

<h3>Methods used to prove that the two triangles are congruent</h3>

Based on the properties of a regular octagon, the diagonals DH and BF

of a regular octagon are perpendicular, and they bisect each other,

given that the length of half the diagonal represent the radius of the

circumscribing circle.

Therefore;

∠NFP ≅ ∠NFP by reflexive property

∠PNF ≅ ∠MOF all right angles are congruent

ΔMOF is similar to ΔPNF by Angle-Angle AA similarity postulate.

∠OMF ≅ ∠DMN by reflexive property

Therefore;

ΔDMN is similar to ΔMOF by AA similarity postulate.

Similarly, we have;

ΔDMN ~ ΔPDO by AA similarity postulate;

Therefore;

ΔPDO is similar to ΔOMF by transitive property

∠ODP ≅ ∠OFM by CASTC, Corresponding Angles of Similar Triangle are Congruent.

OD = OF distance from center to the vertex of a regular octagon are

equal to the radial length of the circumscribing circle and are therefore

equal.

Therefore;

ΔPDO ≅ ΔOMF by Angle-Side-Angle ASA congruency rule

ΔPDO = ΔOMF definition of congruency

ΔHOF ≅ ΔDOF by Side-Angle-Side, SAS, congruency rule

ΔHOF = ΔDOF

ΔFHM = ΔHOF - ΔOMF subtraction property

Similarly

ΔDFP = ΔDOF - ΔPDO = ΔHOF - ΔOMF = ΔFHM by substitution property

ΔDFP = ΔFHM

ΔFHM = ΔDFP by symmetric property.

Therefore;

<u>ΔFHM ≅ ΔDFP by definition of congruency</u>

Learn more about the properties of a regular octagon here:

brainly.com/question/4503941

3 0

2 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Leona [35]

Answer:

1 and 4 are correct. 2 and 3 are not.

Step-by-step explanation:

When x = 0 where does the horse start?

y = 1.5*sin(0 + 0.5)*2*pi + 1.5

y = 1.5*sin(0.5*2pi) + 1.5

y = 1.5*sin(pi) + 1.5 But sin pi = 0

y = 0 + 1.5 So the horse is starting at the midpoint of it's travel.

This one is a trick question. You can reason it without exact answers. At some point the sin(x + 0.5)*2pi will equal 1. When it does 1.5 * 1 + 1.5 = 3.0 At some other point sin(x + 0.5)*2pi = -1. When that happens the whole thing goes to 0. So the total of the distance traveled is 6 not three.

You can figure this one out by letting x = 0.01 When it does then the value of the function is

y = 1.5*sin [(0.01 + 0.5)*2pi] + 1.5

y = 1.5*sin(0.51*2*pi) + 1.5

y = 1.5*sin(3.204424) + 1.5

y = 1.5*(- .0623) + 1.5

y = -0.9418 + 1.5

y = 1.4058 so it is going downward The value is getting smaller.

The horse starts out in the middle of the pole. What does x need to equal so that x + 0.5 = 1 ? And why 1. The answer to why 1 is that then the sine function will equal sin(2*pi)

That happens when x = 0.5 which is 1/2 a minute. If it takes 1/2 a minute to execute 1 complete cycle, then in 5 minutes the cycle will be executed 10 times. This one is correct.

6 0

3 years ago

Cuanto es: 9º 45´´ + 7º 59´ 58´´<br> DIOS BENDIGA AL QUE ME DIGA LA RESPUESTA

lesya692 [45]

Answer:

17° 43"

Step-by-step explanation: