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3 years ago

8

4. If carbon was the most common element found in the moons and planets, what element is missing that would make them similar to

Earth? Explain why. (Hint: Think about the carbon cycle.)

1 answer:

photoshop1234 [79]3 years ago

5 0

Oxygen

Step-by-step explanation:

That's what I think

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Picture shows the question. Please help me with my geometry homework!

lesantik [10]

It is a 68 degree angle.

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3 years ago

Read 2 more answers

Triangle ABC is similar to Triangle DEF, AC=9x, BC=8, DF=18, and EF=x. Which of the following represents the length of AC.

kodGreya [7K]

The answer to your question is 4

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3 years ago

An appliance is for sale at either (a) P15,999 cash or (b) on terms, P1,499 each month for the next 12 months. Money is 9% comp

frutty [35]

Answer:

Cash price

Step-by-step explanation:

The computation is shown below:

The Interest rate per month (r) = (9% ÷ 12) = 0.75%

Now Present value of the monthly payment is

= PMT × {[(1 + rate of interest)^number of years - 1] ÷ rate of interest}

= 1,499 × {[(1 + 0.75%)^12 - 1] ÷ 0.75%}

= 18,748.89

And the cash price is 15,999

So, the cash price would be lower

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3 years ago

Select the correct answer.

malfutka [58]

It is definitely a reflection over the horizontal (x) axis, but i think the dilation is by 2

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2 years ago

The part of a cylindrical soup can that is covered by the label is 8.5 cm tall and has a diameter of 6.5 cm. What is the area of

julia-pushkina [17]

Answer:

$180.4~cm^2$

Step-by-step explanation:

<u>Surface Area</u>

The surface area of a cylinder of height h and radius r is given by:

$A=2\pi rh$

It only covers the lateral side of the cylinder. If both the top and the bottom sides are to be included, then:

$A=2\pi rh+2\pi r^2$

The label will cover only the lateral side of the soup can that has a height of h=8.5 cm and a diameter of 6.5 cm. We need to calculate the radius which is half of the diameter r=6.5 cm / 2 = 3.25 cm.

Now we calculate the side area of the can:

$A=2\pi (3.25)(8.5)$

$A=173.6~cm^2$

We need to add the 0.8 cm overlap to the total area already calculated. This overlap has 0.8 cm of width and 8.5 cm of height, so this overlap area is:

$A_o= 0.8*8.5=6.8~cm^2$

The total area of the label is:

$A=173.6~cm^2+6.8~cm^2=180.4~cm^2$

The area of the label is $\mathbf{180.4~cm^2}$

5 0

2 years ago