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Ostrovityanka [42]
2 years ago
13

Find the missing side length for 15,36 and C

Mathematics
1 answer:
andrew-mc [135]2 years ago
4 0

Answer:

39

Step-by-step explanation:

using pythagorean theorem a squared plus b squared equals c squared 15^2+36^2=C^2

the squared root of C = 225+1296=square root1521 = 39

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Why is it important to know the different properties of three-dimensional figures
IgorLugansk [536]

A two-dimensional shape has length and width. A three-dimensional solid shape also has depth. Three-dimensional shapes, by their nature, have an inside and an outside, separated by a surface. All physical items, things you can touch, are three-dimensional.



4 0
3 years ago
The value of a new truck decreases exponentially at a rate of 4.8% per year. If the purchase price of the new cars $42,000, how
Usimov [2.4K]

The worth of the car after it is paid off 5 years later given the rate of exponential depreciation is $32,842.34.

<h3>What is the worth of the car?</h3>

When the car declines in value, it means that the car is depreciating. The formula that can be used to determine the value of the car with the depreciationn rate is:

FV = P (1 - r)^n

  • FV = Future value
  • P = Present value
  • R = rate of decline
  • N = number of years

$42,000 x (1 - 0.048)^5 = $32,842.34

To learn more about future value, please check: brainly.com/question/18760477

7 0
2 years ago
A particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams. The heavies
RoseWind [281]

Answer:

The heaviest 5% of fruits weigh more than 747.81 grams.

Step-by-step explanation:

We are given that a particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams.

Let X = <u><em>weights of the fruits</em></u>

The z-score probability distribution for the normal distribution is given by;

                              Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean weight = 733 grams

            \sigma = standard deviation = 9 grams

Now, we have to find that heaviest 5% of fruits weigh more than how many grams, that means;

                    P(X > x) = 0.05       {where x is the required weight}

                    P( \frac{X-\mu}{\sigma} > \frac{x-733}{9} ) = 0.05

                    P(Z > \frac{x-733}{9} ) = 0.05

In the z table the critical value of z that represents the top 5% of the area is given as 1.645, that means;

                               \frac{x-733}{9}=1.645

                              {x-733}}=1.645\times 9

                              x = 733 + 14.81

                              x = 747.81 grams

Hence, the heaviest 5% of fruits weigh more than 747.81 grams.

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