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jekas [21]
2 years ago
7

1)

Mathematics
1 answer:
Illusion [34]2 years ago
4 0

Answer:

answer c

Step-by-step explanation: since i helped can i have brainlist please :D

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Find the greatest common factor
timama [110]

<u>answers to 1 - 4:</u>

1.<em> </em><em>GCF: </em>2

2. <em>GCF:</em> 3

3. <em>GCF : </em>7

4.<em> GCF:</em> 3


4 0
3 years ago
The area of a rectangular wall of a barn is 32 square feet. It’s length is 4 feet longer than the width. Find the length and wid
Gnom [1K]

Answer:

Step-by-step explanation:

Givens

Area = L * w

w = x

l = x  + 4

Area = 32

Solution

32 = x(x + 4)

32 = x^2 + 4x

x^2 + 4x - 32

(x + 8)(x - 4)

Only x - 4 is going to make any sense

x - 4 = 0

x = 4

The width is 4

The length is 4 + 4 = 8

4*8 = 32 which is the area.

6 0
3 years ago
So if a shark bites you do you bite it back. and what hit you in the face last night addicted ​
hram777 [196]

Answer:

I dont know what to say

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Find the first three iterates of the function f(z) = z2 + c with a value of c = 2 - 3i and an initial value of z0 = 1 + 2i.
Artist 52 [7]

Answer:

C

Step-by-step explanation:

We have: (I rewrote the function)

f(z_n)={z_{n-1}} ^2+c

Given that:

\displaystyle c=2-3i \text{ and } z_0 = 1 + 2 i

The first iterate will be:

\displaystyle \begin{aligned} f(z_1)&=(z_0)^2+c \\ &=(1+2i)^2+(2-3i) \\ &= (1+4i+4i^2)+(2-3i) \\ &=1+4i-4+2-3i \\ &=-1+i \end{aligned}

The second iterate will be:

\begin{aligned}f(z_2) &=(z_1)^2+c\\ &=(-1+i)^2+(2-3i) \\&= (1-2i+i^2)+(2-3i) \\&=1-2i-1+2-3i \\&=2-5i \end{aligned}

And the third iterate will be:

\begin{aligned} f(z_3)&=(z_2)^2+c\\ &=(2-5i)^2+(2-3i) \\ &=(4-20i+25i^2)+(2-3i) \\ &=4-20i-25+2-3i \\ &=-19-23i \end{aligned}

Hence, our answer is C.

3 0
3 years ago
Finish the steps below to write a quadratic function for the parabola shown. Use the vertex form, f(x) = a(x – h)2 + k, and subs
Marta_Voda [28]
We have

f(x) = a(x – h)²<span> + k
 we know the vertex v(5,3)
</span><span>substitute in the values for h and k
</span>f(x) = a(x – 5)²<span> + 3 
</span><span>Use another point and substitute in values for x and f(x). 
for the point (6,5)
</span><span>Solve for a.
5 = a(6 – 5)2 + 3-------------- > 5=a+3-------------> a=2
</span>
The function is f(x)=a(x – h)2 + k-------- > 2(x – 5)² + 3
f(x)= 2(x – 5)² + 3-------- > 2[x²-10x+25]+3=2x²-20x+50+3=2x²-20x+53
f(x)=2x²-20x+53
<span>
the answer is f(x)=</span> 2(x – 5)² + 3----------------- > (f(x)=2x²-20x+53)<span>

</span>
8 0
3 years ago
Read 2 more answers
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