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shtirl [24]
3 years ago
9

Please Help Me Due Today!! Major points!!!

Mathematics
2 answers:
Pachacha [2.7K]3 years ago
5 0

Answer:CASE #1 - Divergent and convergent one-way

residential streets to reduce direct through

routes impacting the neighborhood.

CASE #2 - Alternating one-way streets throughout a

portion of a grid system to gain safety

advantages of one-way operations.

CASE #3 - Creating a one-way couplet by paring a

residential street with a nearby thru street to

create a corridor for thru traffic

Step-by-step explanation:

Dafna11 [192]3 years ago
5 0
Can i get more context on it ? like is there a picture or anything ??
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1. Which of the following questions has a constant of
garik1379 [7]

Answer:

In B)  y = x/7 , the constant of proportionality is 7.

Step-by-step explanation:

Two quantities X and Y are said to be in proportion if and only if

X = kY   or, \frac{X}{Y}  = k,

where k =  Proportionality Constant.

Here, 7 is the constant of proportionality. Then,

A .   y = 14x

here, \frac{y}{x}  = 14  ≠ 7

B .   y = x/7

here, \frac{x}{y}  = 7  = constant of proportionality .

C.   y = x

here, \frac{y}{x}  = 1  ≠ 7

4 0
3 years ago
Please help, i’ll mark brainliest.
nalin [4]

Answer:

264 cu

Step-by-step explanation:

This is because you have to add it from all sides, the first prism is 144 cu and then the second one is, 120, and when you add both of those together you get 264

<u><em>Thus the answer is....264</em></u>

5 0
3 years ago
Which table represents a linear function?
Nutka1998 [239]

Answer:

The third option

Step-by-step explanation:

The slope is a constant linear slope of 8

7 0
3 years ago
What is the equation of a parabola with vertex (0,0) and focus (0,4)?<br> Draw its graph on the grid
svp [43]
Focus of a parabola: 4p(y-k)=(x-h)^2 where vertex (h,k) p is the distance from vertex to focus
4*4(y-0)=(x-0)^2 \\ 16y=x^2 \\ y= \frac{1}{16}x^2

3 0
3 years ago
The figure is made up of a square and a rectangle. Find the area of the shaded region 16 by 3 by 7
FrozenT [24]

Answer:

Go on Answers.com your welcome.

4 0
3 years ago
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