Answer:
Step-by-step explanation:
- Therfore theta is QI
- Therfore sin theta >0
Answer:
P = 0.006
Step-by-step explanation:
Given
n = 25 Lamps
each with mean lifetime of 50 hours and standard deviation (SD) of 4 hours
Find probability that the lamp will be burning at end of 1300 hours period.
As we are not given that exact lamp, it means we have to find the probability where any of the lamp burning at the end of 1300 hours, So we have
Suppose i represents lamps
P (∑i from 1 to 25 ( > 1300)) = 1300
= P(> ) where represents mean time of a single lamp
= P (Z> ) Z is the standard normal distribution which can be found by using the formula
Z = Mean Time () - Life time of each Lamp (50 hours)/ (SD/)
Z = (52-50)/(4/) = 2.5
Now, P(Z>2.5) = 0.006 using the standard normal distribution table
Probability that a lamp will be burning at the end of 1300 hours period is 0.006
Answer:
2.57 or 2.5703939893007399
Hope this helped have a good one! :)
When y=3/x translated right 3 units , we get y = 3/(x-3).
Then we translate y = 3/(x-3) , 3 units up and get y = 3/(x-3) +3.
So the answer is B.
y=3/(x-3) + 3