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rodikova [14]
3 years ago
9

Are the graphs of the lines in the pair parallel? Explain.

Mathematics
1 answer:
jonny [76]3 years ago
7 0
You need to convert the second equation to slope/intercept form. The first equation is in that form already. Then you can compare  slopes.

-6x + 8y = 14
8y = 6x + 14
y = (3/4)x + 14/8

SO THE SLOPE IS 3/4 which is the same as slope of equation 1

Therfore they are parallel.
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Answer:

First, find tan A and tan B.

cosA=35 --> sin2A=1−925=1625 --> cosA=±45

cosA=45 because A is in Quadrant I

tanA=sinAcosA=(45)(53)=43.

sinB=513 --> cos2B=1−25169=144169 --> sinB=±1213.

sinB=1213 because B is in Quadrant I

tanB=sinBcosB=(513)(1312)=512

Apply the trig identity:

tan(A−B)=tanA−tanB1−tanA.tanB

tanA−tanB=43−512=1112

(1−tanA.tanB)=1−2036=1636=49

tan(A−B)=(1112)(94)=3316

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