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Mama L [17]
2 years ago
11

Someone help me plss​

Mathematics
2 answers:
Olenka [21]2 years ago
8 0
9) twelve
10)10,000
11) fifty and four fifths
12)3,000
13).45
14)54
15)378
yan [13]2 years ago
7 0

9. 12 edges

Work: <u>4</u> horizontal edges on top, <u>4</u> horizontal edges on bottom, <u>4</u> vertical edges for sides

10. Ten-thousands place

Work: The 8 is highlighted. The order of places is: <u>ten-thousands</u>, thousands, hundreds, tens, ones

11. 10 4/5

Work: 54 ÷ 5 ——> 50÷5 = <u>10</u> with 4 left over and put into a fraction of <u>4/5</u>

12. 3,000

Work: 2 is in the thousands place so you look to the place behind it and there is an 8. If the number behind is 5 through 9 then you round up. 8 is above 5, therefore, you round the 2 up to a <u>3</u>.

13. 0.45

Work: The pattern is +0.03 so 0.42+0.03=<u>0.45</u>

14. 54 cakes

Work: <u>6 eggs</u> per 1 cake • <u>9 cakes</u> = 6•9=54 eggs used

15. 378 desks in the school

Work: 6 rows • 7 desks per row = 42 desks in 1 classroom. 42 desks • 9 classrooms = 378 desks in the whole school

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Any help would be greatly appreciated!
Aleks [24]

Answer:

the answer for that question is sqrt(49)

7 0
2 years ago
Read 2 more answers
there are 245 students in 7th grade if 40% of them ride the bus to school how many 7th graders do not ride the bus to school? F
Ivenika [448]
Multiply 245 by .40 (which is 40%)
245 x (.40)= 98. When you get 98, you have to 245-98 and you get 147
3 0
3 years ago
On a model castle, 1 inch equals 83 feet. The model is 10.5 inches wide. What is the actual width of the castle?
Furkat [3]

Answer:

871 and 1/2 ft.  

8 0
3 years ago
Please help: linear algebra problem. (Linear combinations)
DochEvi [55]

Answer:

\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

This tells us that:

A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]

b=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

Step-by-step explanation:

So we are saying we have scalars, c and d, such that:

c\left[\begin{array}{ccc}5\\5\\ 3\end{array}\right]+d\left[\begin{array}{ccc}7\\-8\\-9\end{array}\right]=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right].

So we want to find a way to express this as:

Ax=b where x is the scalar vector, \left[\begin{array}{ccc}c\\d\end{array}\right].

So we can write this as:

\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

3 0
2 years ago
Solve the equation -25+4y=35
borishaifa [10]
-25+4y=35
*Subtract 35*
-25+4y-35=0
*add 25 (to cancel out)*
4y-35=25
*add 35 (to cancel out)*
4y=60
*Divide by 4 to get y on its own*
y=15
Hope this helps :)
6 0
2 years ago
Read 2 more answers
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