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olga nikolaevna [1]
4 years ago
14

Hi:) I need help with 11(a) , thanks!:))

Mathematics
1 answer:
Irina-Kira [14]4 years ago
7 0

Answer:

18.95

Step-by-step explanation:

ln 2 x ln (4x) = 3

ln 4x = = 3 / ln 2

ln4x =  3 / 0.69315 = 4.3281

4x = e^4.328 = 75.80

x =  18.95.

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Which set of ordered pairs could be generated by an exponential function?
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Answer:

The correct option is  (1,2), (0, 1), (1, 2), (2, 4).

Step-by-step explanation:

Consider the provided ordered pairs.

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Hence, the correct option is  (1,2), (0, 1), (1, 2), (2, 4).

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Families USA, a monthly magazine that discusses issues related to health and health costs, surveyed 20 of its subscribers. It fo
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(a) The 90 percent confidence interval for the population mean yearly premium is ($10,974.53, $10983.47).

(b) The sample size required is 107.

Step-by-step explanation:

(a)

The (1 - <em>α</em>)% confidence interval for population mean is:

CI=\bar x\pm t_{\alpha/2, (n-1)}\times \frac{s}{\sqrt{n}}

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*Use a <em>t-</em>table.

Compute the 90% confidence interval for population mean as follows:

CI=\bar x\pm t_{\alpha/2, (n-1)}\times \frac{s}{\sqrt{n}}

     =10979\pm 1.729\times \frac{1000}{\sqrt{20}}\\=10979\pm4.47\\ =(10974.53, 10983.47)

Thus, the 90 percent confidence interval for the population mean yearly premium is ($10,974.53, $10983.47).

(b)

The margin of error is provided as:

MOE = $250

The confidence level is, 99%.

The critical value of <em>z</em> for 99% confidence level is:

z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.58

Compute the sample size as follows:

MOE= z_{\alpha/2}\times \frac{s}{\sqrt{n}}

      n=[\frac{z_{\alpha/2}\times s}{MOE} ]^{2}

         =[\frac{2.58\times 1000}{250}]^{2}

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Thus, the sample size required is 107.

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