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3 years ago

B. Find the balance of the account. $

Mathematics

1 answer:

DiKsa [7]3 years ago

4 0

What account? :| it doesn’t have an image or anything

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Which graph represents a quadratic function with a vertex at (0, 0)?

maxonik [38]

The 3rd one. (where the round part of the graph is at 0, 0) because that is where the y axis meets

7 0

3 years ago

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What is the slope of the line that passes through the points (-2, -1) and (2, -3)?

Lady bird [3.3K]

Answer:

$m=\frac{-1}{2}$

Step-by-step explanation:

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>:

$m=\frac{-3-(-1)}{2-(-2)}$

$m=\frac{-3+1}{2+2}$

$m=\frac{-2}{4}$

$m=\frac{-1}{2}$

3 0

3 years ago

I need to know is the answer

photoshop1234 [79]

Answer:the aser is d

please give me branlest

im a danged expert

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Please help for 10 points and 5 stars with 1 thanks! :]

Rudiy27

probability = favourable outcomes/total outcomes

you need 1 banana, out of 4 and there are total of 6 items so probability will be 4/6

when you take out 1 banana, there are 3 banana left and total of 5 items

so probability of this action will be 3/5

now, next action is taking out another banana.

this is NOT an independent event.

so by we will multiply the probabilities of these events according to rule of products.

so the answer is $\frac{4\cdot3}{6\cdot5}=\frac25$

or 2×100/5=40%

7 0

3 years ago

A parabola can be drawn given a focus of (-5, -4)(−5,−4) and a directrix of y=-6y=−6. Write the equation of the parabola in any

lord [1]

Answer:

$\displaystyle \large{y=\dfrac{x^2}{4} + \dfrac{5x}{2} + \dfrac{5}{4}}$

Step-by-step explanation:

Given:

Focus = (-5,-4)
Directrix = -6

To find:

Parabola Equation

Locus of Parabola (Upward/Downward)

$\displaystyle \large{\sqrt{(x-a)^2+(y-b)^2} = |y-c|}$

Where:

(a,b) = focus
c = directrix

Hence:

$\displaystyle \large{\sqrt{(x+5)^2+(y+4)^2}=|y+6|}$

Cancel square root by squaring both sides as we get:

$\displaystyle \large{(x+5)^2+(y+4)^2=(y+6)^2}$

Solve for y-term:

$\displaystyle \large{(x+5)^2=(y+6)^2-(y+4)^2}\\\displaystyle \large{x^2+10x+25=y^2+12y+36-y^2-8y-16}\\\displaystyle \large{x^2+10x+25=4y+20}\\\displaystyle \large{x^2+10x+5=4y}\\\displaystyle \large{y=\dfrac{x^2}{4} + \dfrac{5x}{2} + \dfrac{5}{4}}$

4 0

2 years ago