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Inessa [10]
3 years ago
14

What is the degree measure of an arc 4 pie ft long in a circle of radius 10 ft

Mathematics
1 answer:
Bess [88]3 years ago
7 0

Answer:

ow do you find arc length without the radius?

To calculate arc length without radius, you need the central angle and the sector area:

Multiply the area by 2 and divide the result by the central angle in radians.

Find the square root of this division.

Multiply this root by the central angle again to get the arc length.

The units will be the square root of the sector area angle.

Check your result with Omni Calculator.

Or the central angle and the chord length:

Divide the central angle in radians by 2 and perform the sin function on it.

Divide the chord length by double the result of step 1. This gives you the radius.

Multiply the radius by the central angle to get the arc length.

Check your result with Omni Calculator

Step-by-step explanation:

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Can someone tell me what 2/3 divided by 5 is it’s for a quiz.
docker41 [41]

Answer:2/15 hope this helps

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Plssssss help meh with this
Naddik [55]

Answer:

<h2><em><u>ᎪꪀsωꫀᏒ</u></em></h2>

➪-263

Step-by-step explanation:

-3x²-20

-3(-9)²-20

-3(81)-20

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5 0
2 years ago
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Only number one please help ​
Alex73 [517]

Answer:

C) 75 + 50x = 25 + 70x

Step-by-step explanation:

ABC Tech:

$50 an hour. So,for x hours= 50 * x = 50x

Service charge = 75 + 50x

Tech Squad:

$70 an hour. So,for x hours= 70 * x = 70x

Service charge = 25 + 70x

C) 75 + 50x = 25 + 70x

50x - 70x = 25 - 75

-20x = -50

x = -50/-20

x =5/2 = 2\frac{1}{2}hours

6 0
3 years ago
Expand the expression and combine like terms.(2+2w)⋅4+9(w+3)
Nonamiya [84]
0.8+0.8w+9w+27
9.8w+27.8

3 0
3 years ago
The coordinates of polygon ABCD are A(-4,-1), B(-2,3), C(2,2), and D(4,-3). Use these coordinates to complete the sentences belo
oee [108]

Answer:

The perimeter of polygon ABCD, to the nearest thousandth units is

22.227 units

The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

The area of polygon ABCD' is 19.5 units²

Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

Length of line between two X and Y points distance, xi and yj apart is

length XY =  \sqrt{x^2+y^2}

Therefore, the length between points AB is

length AB = \sqrt{(-4 - (-2))^2+(-1-3)^2}

= \sqrt{(-4 +2)^2+(-4)^2} = \sqrt{-2^2+-4^2}  = \sqrt{20}  = 4.472 units

Similarly, length BC is given by

Length BC =  \sqrt{(-4)^2+1^2} =  \sqrt{17} = 4.123 units

Length CD = \sqrt{(-2)^2+5^2} =  \sqrt{29} = 5.385 units

Length DA = \sqrt{(8)^2+(-2)^2} =  \sqrt{68} = 8.246 units

The perimeter is equal to;

length AB + Length BC + Length CD + Length DA

= 4.472 + 4.123 + 5.385 + 8.246 = 22.227 units

If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A =  \sqrt{(7)^2+(0)^2} =  \sqrt{49} =7 units

The perimeter of polygon ABCD'

length AB + Length BC + Length CD + Length D'A

= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

 S_{\bigtriangleup} = (\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|

= (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

Triangle ABC we have

A(-4,-1)

B(-2,3)

C(2,2)

S_{{\bigtriangleup}ABC} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(3-2)+(-2)(2-(-1)) +2((-1)-3)|

= =(\frac{1}{2})|-4-6 -8|= 9 units^2

Triangle ACD'

A(-4,-1)

C(2,2)

D'(3, -1)

S_{{\bigtriangleup}ACD'} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(2+1)+(2)(-1+1) +3((-1)-2)| = \frac{21}{2} = 10.5 units²

Area of polygon =   S_{{\bigtriangleup}ABCD'} = S_{{\bigtriangleup}ABC} + S_{{\bigtriangleup}ACD'} = (9 + 10.5) units²

Area of polygon ABCD' = 19.5 units².

7 0
3 years ago
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