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Lunna [17]
3 years ago
7

A square postage stamp has area 1240 mm^2 about how long is each side?

Mathematics
1 answer:
Shtirlitz [24]3 years ago
6 0
Sq.root of 1240 is approx 35 mm
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Brendan is building a dog house, and the
Pani-rosa [81]

Answer:

B. 46 ft²

Step-by-step explanation:

Two sides are rectangles 3.1 ft by 5 ft.

One side is a rectangle 5 ft by 3 ft.

area = 2(3.1 ft × 5 ft) + (5 ft × 3 ft)

area = 46 ft²

8 0
3 years ago
Plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
Cerrena [4.2K]
I you think about it 12a with the 2 on the rope is actually 144 because it’s multiplied by 12 so maybe that helps?
6 0
3 years ago
Which of the following sets of points is a direct variation? (0, 0); (2, 4); (5, 15) (0, 0); (-1, -2); (1, 2) (3, 6); (-2, 4); (
chubhunter [2.5K]
I believe that the best answer among the choices provided by the question is the first choice, <span>( 0 ,  0 ) ;  ( 2 ,  4 )</span>
Hope my answer would be a great help for you.    If you have more questions feel free to ask here at Brainly.
4 0
4 years ago
Read 2 more answers
Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)
viktelen [127]
\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}

The first line segment can be parameterized by \mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle with 0\le t\le1. Denote this first segment by C_1. Then

\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt
=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt
=108

The second line segment (C_2) can be described by \mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle, again with 0\le t\le1. Then

\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt
=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt
=-\dfrac{229}3

Finally,

\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3
5 0
3 years ago
The question is in the picture. The answer is 14 but I don't know how to get that.
andrezito [222]
Let's convert the problem into Arithmetic progression:
It would be: 5, 9, 13, .... 

Here, a = 5, d = 9 - 5 = 4
We know, S(n) = n/2 [ 2a + (n-1)d ]

Substitute the known values, 
434 = n/2 [ 2(5) + (n - 1)4 ]
434 * 2 = n [ 10 + 4n - 4 ]
868 = 10n + 4n² - 4n
= 4n² + 6n - 868 = 0

d = b² - 4ac
d = 6² - 4(4)(-868)
d = 36+13888
d = 13924

Now, roots = -b +- √d / 2a
= (-6 + √13924) / 2(4)   OR  (-6 - √13924) / 2(4)
= (-6 + 118) / 8   OR  (-6 - 118) / 8
= 112/8  OR  -124/8
= 14 OR -15.5

As number of sticks can't be in negative/decimal or fraction form, -15.5 would be fully rejected.

In short, Your Answer would be 14 [ Remaining root ]

Hope this helps!
7 0
3 years ago
Read 2 more answers
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