All categories

3 years ago

Which of these prices is lower than 8 for $10.00?

Mathematics

1 answer:

nadya68 [22]3 years ago

3 0

11 for $12

hope this helps!

You might be interested in

PLS HELP I WILL MARK BRAINLIST IF CORRECT!!! :)

GrogVix [38]

Answer:

A is the answer to the question because in a expression you have to do the paréntesis first.

4 0

3 years ago

How can you prove that csc^2(θ)tan^2(θ)-1=tan^2(θ)

Oxana [17]

Answer:

Make use of the fact that as long as $\sin(\theta) \ne 0$ and $\cos(\theta) \ne 0$ :

$\displaystyle \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}$ .

$\displaystyle \csc(\theta) = \frac{1}{\sin(\theta)}$ .

$\sin^{2}(\theta) + \cos^{2}(\theta) = 1$ .

Step-by-step explanation:

Assume that $\sin(\theta) \ne 0$ and $\cos(\theta) \ne 0$ .

Make use of the fact that $\tan(\theta) = (\sin(\theta)) / (\cos(\theta))$ and $\csc(\theta) = (1) / (\sin(\theta))$ to rewrite the given expression as a combination of $\sin(\theta)$ and $\cos(\theta)$ .

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \left(\frac{1}{\sin(\theta)}\right)^{2} \, \left(\frac{\sin(\theta)}{\cos(\theta)}\right)^{2} - 1 \\ =\; & \frac{\sin^{2}(\theta)}{\sin^{2}(\theta)\, \cos^{2}(\theta)} - 1\\ =\; & \frac{1}{\cos^{2}(\theta)} - 1\end{aligned}$ .

Since $\cos(\theta) \ne 0$ :

$\displaystyle 1 = \frac{\cos^{2}(\theta)}{\cos^{2}(\theta)}$ .

Substitute this equality into the expression:

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots\\ =\; & \frac{1}{\cos^{2}(\theta)} - 1 \\ =\; & \frac{1}{\cos^{2}(\theta)} - \frac{\cos^{2}(\theta)}{\cos^{2}(\theta)} \\ =\; & \frac{1 - \cos^{2}(\theta)}{\cos^{2}(\theta)}\end{aligned}$ .

By the Pythagorean identity, $\sin^{2}(\theta) + \cos^{2}(\theta) = 1$ . Rearrange this identity to obtain:

$\sin^{2}(\theta) = 1 - \cos^{2}(\theta)$ .

Substitute this equality into the expression:

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots \\ =\; & \frac{1 - \cos^{2}(\theta)}{\cos^{2}(\theta)} \\ =\; & \frac{\sin^{2}(\theta)}{\cos^{2}(\theta)}\end{aligned}$ .

Again, make use of the fact that $\tan(\theta) = (\sin(\theta)) / (\cos(\theta))$ to obtain the desired result:

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots \\ =\; & \frac{\sin^{2}(\theta)}{\cos^{2}(\theta)}\\ =\; & \left(\frac{\sin(\theta)}{\cos(\theta)}\right)^{2} \\ =\; & \tan^{2}(\theta)\end{aligned}$ .

5 0

2 years ago

A bag contains 8 red crayons, 14 purple crayons, 6 yellow crayons, and 4 green crayons. A crayon is selected, replaced, and then

lys-0071 [83]

Answer:

P(yellow the red) = $\frac{3}{32}$

Step-by-step explanation:

P(yellow and red) = P(yellow then red) + P(red then yellow)

P(yellow then red) = $\frac{6}{32} . \frac{8}{32} = \frac{3}{64}$

P(red then yellow) = P(yellow then red)

P(yellow and red) = $\frac{3}{64} + \frac{3}{64} = \frac{3}{32}$

5 0

3 years ago

If m <2 = 44, find the measure of an angle that is supplementary to <4 .

Montano1993 [528]

Answer:

136

Step-by-step explanation:

if two angles are supplementary then they have to add up 180. So if the measure of angle 2 is supplementary to the measure of angle 4 they have to add up to 180. you subtract 44 from 180 and you get 136. The measure of angle 4 is 136. 136 makes these two angles supplementary.

3 0

4 years ago

james has a piece of construction paper with an area of 65 1/4 inches is 9 2/3 inches long. What is the width of a piece of cons

Aneli [31]

divide 65 1/4 with 9 2/3 you will get 6 3/4.

so width is 6 3/4

3 0

3 years ago

Read 2 more answers