(a) 3675 N
Assuming that the acceleration of the rocket is in the horizontal direction, we can use Newton's second law to solve this part:
where
is the horizontal component of the force
m is the mass of the passenger
is the horizontal component of the acceleration
Here we have
m = 75.0 kg
Substituting,
(b) 3748 N, 11.3 degrees above horizontal
In this part, we also have to take into account the forces acting along the vertical direction. In fact, the seat exerts a reaction force (R) which is equal in magnitude and opposite in direction to the weight of the passenger:
where we used
as acceleration of gravity.
So, this is the vertical component of the force exerted by the seat on the passenger:
and therefore the magnitude of the net force is
And the direction is given by
<h3><u>Answer;</u></h3>
Energy
<h3><u>Explanation;</u></h3>
- A wave is a transmission of disturbance from one point to another. All waves involve transmission of energy from one point called the source to another point.
- <em><u>Waves describes various ways in which energy can be transferred from a point source.</u></em>
- <em><u>In electromagnetic waves</u></em><em>, for instance, </em><em><u>energy transmission occurs as a result of vibrations of electric and magnetic fields</u></em><u>.</u>
- <u><em>In mechanical waves energy transmission is as a result of vibration of particles in the medium used</em></u>. For example in sound waves, energy is transferred through vibration of particles of air or particles of a solid or medium through which sound travels through.
Substract two consecutive terms of the sequence to see if there is a common difference:
As we can see, there is a common difference of -6.
Then, if a number of the sequence is given, the next one can be found by adding -6 (which is the same as subtracting 6).
Notice that the first term of the sequence is 3.
Then, the rule for the sequence is to start with 3 and add -6 repeatedly.
Therefore, the correct choice is option A) Start with 3 and add -6 repeatedly.
Answer:
B. About 12 degrees
Explanation:
The orbital period is calculated using the following expression:
T = 2π*(
)
Where r is the distance of the planet to the sun, G is the gravitational constant and m is the mass of the sun.
Now, we don't actually need to solve the values of the constants, since we now that the distance from the sun to Saturn is 10 times the distance from the sun to the earth. We now this because 1 AU is the distance from the earth to the sun.
Now, we divide the expression used to calculate the orbital period of Saturn by the expression used to calculate the orbital period of the earth. Notice that the constants will cancel and we will get the rate of orbital periods in terms of the distances to the sun:
= 
Knowing that the orbital period of the earth is 1 year, the orbital period of Saturn will be 
years, or 31.62 years.
We find the amount of degrees it moves in 1 year:
or about 12 degrees.
