Answer:
Explanation:
The force to which the object of mass <em>m</em> is attracted to a star of mass <em>M</em> while being at a distance <em>r</em> is:
Where 
is the gravitational constant.
Also, Newton's 2nd Law tells us that this object subject by that force will experiment an acceleration given by <em>F=ma.</em>
We have then:
Which means:
The object departs from rest (
) and travels a distance <em>d</em>, under an acceleration <em>a</em>, we can calculate its final velocity with the formula 
, which for our case will be:
We assume <em>a</em> constant on the vecinity of the surface because d=0.025m is nothing compared with 
. With our values then we have:
Apple basket hope this helped
Answer:
the value of vA that will allow the car to coast in neutral so as to just reach the top of the 150 m high hill at B with vB = 0 is 31.3 m/s
Explanation:
given information
car's mass, m = 1200 kg
= 100 m
=
= 150 m
= 0
according to conservative energy
the distance from point A to B, h = 150 m - 100 m = 50 m
the initial speed
final speed = 0
thus,
² = ² - 2 g h
0 = ² - 2 g h
² = 2 g h
= √2 g h
= √2 (9.8) (50)
= 31.3 m/s
+X axis is passing through from +75 to +48. then to _83
Now force on +75 due to +48 is being repulsive, with the direction -X, So the X component of force is negative.
Force on +75 due to -85 is attractive, with the direction of +X.
∴ The X component of force is positive
K is always constant and positive.
