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Answer:
1.
2.543.6
Step-by-step explanation:
We are given that
y(0)=200
Let y be the number of bacteria at any time
=Number of bacteria per unit time
Where k=Proportionality constant
2.,y'(0)=100
Integrating on both sides then, we get
We have y(0)=200
Substitute the values then , we get
Substitute the value of C then we get
Differentiate w.r.t
Substitute the given condition then, we get
Substitute t=2
Then, we get
e=2.718
Hence, the number of bacteria after 2 hours=543.6
Given equation : n(17+x)=34x−r.
We need to solve it for x.
Distributing n over (17+x) on left side, we get
17n + nx = 34x - r.
Adding r on both sides, we get
17n+r + nx = 34x - r+r.
17n + r + nx = 34x.
Subtracting nx from both sides, we get
17n + r + nx-nx = 34x-nx
17n + r = 34x -nx.
Factoring out gcf x on right side, we get
17x + r = x(34-n).
Dividing both sides by (34-n), we get