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Butoxors [25]
3 years ago
10

Find y Round to the nearest tenth: 29 500 ft y х y = [ ? ]ft

Mathematics
1 answer:
Ilya [14]3 years ago
7 0

Answer:

242.4

Step-by-step explanation:

y = 500×sin 29°

= 500× 0.4848

= 242.4 ft

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A sandbox has a perimeter of 21 1/2 feet. If the length is 5 1/4 feet, what is the area of the sand box?
LiRa [457]
The perimeter of a rectangle is twice the sum of length and width, so the sum of length and width is half the perimeter, 10 3/4 ft.

The width will be the difference between this and the length, hence 5 1/2 ft.

The area is the product of length and width.
  A = length×width
  A = (5.25 ft)×(5.5 ft) = 28.875 ft²

The area of the sandbox is 28 7/8 ft².
4 0
3 years ago
Can someone help me on this?
dezoksy [38]

Answer:

C

Step-by-step explanation:

divide 22.5 by 10

=2.5

so

f=2 1/2c

8 0
3 years ago
D = √[( x₂ - x₁) + (y₂ - y₁)]
kondaur [170]
As it stands, it's none of those. I believe you were going for the distance formula but copied it wrong.
7 0
3 years ago
Read 2 more answers
When the positive integer x is divided by 11, the quotient is y and the remainder 3. When x is divided by 19, the remainder is a
Lyrx [107]

Answer:

A) 0

Step-by-step explanation:

When x is divided by 11, we have a quotient of y and a remainder of 3

x/11 = y + 3

x = 11y + 3 ........(1)

When x is divided by 19, we have a remainder of 3 also

x/19 = p + 3 (p = quotient)

x = 19p + 3 ..........(2)

Equate (1) and (2)

x = 11y + 3 = 19p + 3

11y + 3 = 19p + 3

11y = 19p + 3 -3

11y = 19p

Divide both sides by 11

11y/11 = 19p/11

y = 19p/11

y and p are integers. 19 is a prime number. P/11 is also an integer

y = 19(integer)

This implies that y is a multiple of 19. When divided by 19, there is no remainder. The remainder is 0

8 0
3 years ago
Use (<,>,=) to compare 2/3 and 3/4
lina2011 [118]
2/3 < 3/4. Hope that helps
3 0
3 years ago
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