Can someone pls give answer to number 4
2 answers:
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Given:
Elise is making punch for the party that requires 2 parts of fruit juice for every 5 parts of ginger ale.
To make the punch, she uses 18 ounces of fruit juice and 3 containers of ginger ale.
To find:
The number of ounces in each container of ginger ale.
Solution:
Let n be the number of ounces in each container of ginger ale.
According to the question, the ratio of fruit juice and ginger ale is 2:5. it means,
Divide both sides by 2.
So, ginger required for punch is 45 ounces.
Number of containers = 3
Number of ounces in each container of ginger ale = n
Number of ounces in 3 containers of ginger ale = 3n
Now,
Divide both sides by 3.
Therefore, 15 ounces are in each container of ginger ale.
Answer:
Now we can find the degrees of freedom:
Now we can calculate the p value with the alternative hypothesis using the following probability:
Using a significance level of 0.01 or 1% we have enough evidence to FAIL to reject the null hypothesis and we can conclude that shoppers participating in the loyalty program NOT spent more on average than typical shopper at this significance level assumed
Step-by-step explanation:
Information given
represent the sample mean
represent the sample standard deviation
sample size
represent the value to verify
t would represent the statistic
represent the p value
System of hypothesis
We want to verify if shoppers participating in the loyalty program spent more on average than typical shoppers (120) , the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
The statistic for this case is given by:
(1)
Replacing the info given we got:
Now we can find the degrees of freedom:
Now we can calculate the p value with the alternative hypothesis using the following probability:
Using a significance level of 0.01 or 1% we have enough evidence to FAIL to reject the null hypothesis and we can conclude that shoppers participating in the loyalty program NOT spent more on average than typical shopper at this significance level assumed