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AveGali [126]
3 years ago
11

Please help

Mathematics
2 answers:
algol133 years ago
7 0
Her balance was $455 before writing the check
gayaneshka [121]3 years ago
4 0

Answer:

She had $455 before

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Help please with steps
SOVA2 [1]

From the image, we can see the amount of water in Liters are in the beaker.

The beaker is marked with numbers that are skip counting by 10. (10,20,30) so on. There are 4 ticks below the 10, 5 if you count the 10.

So that means 10/5 = 2 L per tick.

The water goes above the 30 mark and under the 40 mark, which means it's somewhere in the 30's.

Since each tick is 2 L, and the water goes to the third tick:

2L + 2L + 2L = 6L.

Add 6L to 30: 30+ 6L = 36L

6 0
3 years ago
Read 2 more answers
A) Work out the value of 5^2-1^5 x 2^4
Mekhanik [1.2K]

Answer: 9

Step-by-step explanation

3 0
3 years ago
There is a bag of marbles with 7 blue marbles, 7 yellow marbles, and 7 red marbles. You are going to choose one marble at random
arsen [322]

(Since there are no options to chose from, I guess I'll just do my own answer and you'll have to pick the closest one to this one. Or, you could comment the options and I could help you there too.)

Answer:

Yes, the outcomes are likely because there is an equal number of each type of marble.

Step-by-step explanation:

Since there is an equal number of each color of marble, the outcomes of the event are equally likely. If there were more of one marble, it would be unlikely.

For example, if there were 7 blue marbles, 7 red marbles, but there were 8 yellow marbles, then the event would be unequally likely because there were more of the yellow marbles.  So the answer is yes, the outcomes are equally likely.

It would be FANTABULOUS if I could get BRAINLIEST!!!!!!!

Have a great day!! ;p

5 0
3 years ago
There are 90 new houses being built in a neighborhood. Last month, 2/5 of them were sold. This month, 2/3 of the remaining house
aleksklad [387]

Answer:

18

Step-by-step explanation:

2/5*90=36

90-36=54

2/3*54=36

54-36=18

8 0
3 years ago
The compound interest on a sum of money in
Yakvenalex [24]

Answer:

The difference between the principal and the compound interest in three years is Rs 17,994

Step-by-step explanation:

The compound interest is given according to the following formula;

C.I. = P \cdot \left ( 1 + \dfrac{r}{n} \right ) ^{n\cdot t} - P

The given amount of the compound after 2 years = Rs 5,460

The given amount of the compound after 4 years = Rs 12,066.60

Therefore, we have;

5,460 = P \cdot \left ( 1 + \dfrac{r}{100} \right ) ^{2} - P...(1)

12,066.60 = P \cdot \left ( 1 + \dfrac{r}{100} \right ) ^{4} - P ...(2)

Dividing equation (2) by (1), we have;

\dfrac{12,066.60}{5,460} = \dfrac{P \cdot \left ( \left ( 1 + \dfrac{r}{100} \right ) ^{4} - 1\right )}{P \cdot \left (\left ( 1 + \dfrac{r}{100} \right ) ^{2} -1 \right ) } =\dfrac{\left ( 1 + \dfrac{r}{100} \right ) ^{4} - 1}{\left ( 1 + \dfrac{r}{100} \right ) ^{2} -1  }

Let \  \left ( 1 + \dfrac{r}{100} \right ) ^{2} = x, we \ get;

\dfrac{12,066.60}{5,460} =\dfrac{\left ( 1 + \dfrac{r}{100} \right ) ^{4} - 1}{\left ( 1 + \dfrac{r}{100} \right ) ^{2} -1  } = \dfrac{x^2 - 1}{x - 1}

∴ 12,066.60 × (x - 1) = 5,460 × (x² - 1) = 5,460 × (x - 1) ×(x + 1)

∴ 12,066.60 × (x - 1)/(x - 1) = 5,460 × (x + 1)

12,066.60/5,460 = x + 1

x =  12,066.60/5,460 - 1 = 1.21 = 121/100

x = 121/100

\left ( 1 + \dfrac{r}{100} \right ) ^{2} = x = \dfrac{121}{100}

1 + \dfrac{r}{100}   =\sqrt{ \dfrac{121}{100}} = \dfrac{11}{10}

We get

\dfrac{12,066.60}{5,460} =\dfrac{221}{100}

\therefore \dfrac{12,066.60}{5,460} =\dfrac{221}{100} = \left ( 1 + \dfrac{r}{100} \right ) ^{2}

1 + \dfrac{r}{100} = \sqrt{ \dfrac{221}{100} } = \dfrac{\sqrt{221} }{10}

\dfrac{r}{100} = \dfrac{\sqrt{221} }{10} - 1

\dfrac{r}{100}   = \dfrac{11}{10} - 1 = \dfrac{1}{10} = 0.1

r = 100 × 0.1 = 10%

r = 10%

Therefore, we have;

5,460 = P \cdot \left ( 1 + \dfrac{r}{100} \right ) ^{2} - P = P \times \left ( 1 + 0.1\right ) ^{2} - P

5,460  = P \times \left ( 1 + 0.1\right ) ^{2} - P = P \times \left (\left ( 1 + 0.1\right ) ^{2} - 1\right) = P \times \dfrac{21}{100}

P = \dfrac{100}{21} \times 5,460 = 26,000

The principal = Rs. 26,000

The compound interest in 3 years is therefore;

CI_3 = 26,000 \times \left ( 1 + \dfrac{10}{100} \right ) ^{3} - 26,000= 8606

The difference, 'd', between the principal and the compound interest in three years, is given as follows;

d = P - CI₃

d = 26,600 - 8606 = 17994

The difference between the principal and the compound interest in three years, d = Rs 17,994.

5 0
3 years ago
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