The domain and range of a function is the set of input and output values, the function can take.
- <em>The domain is [0,6]</em>
- <em>The range is [0,90]</em>
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From the question, we have:

<u>The domain</u>
He cannot mow more than 6 yards a day.
This means that the domain is: 0 to 6
<em>This is properly represented as: [0,6]</em>
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<u>The range</u>
When he mows 0 yards, his earnings is:

When he mows 6 yards, his earnings is:

This means that the range is: 0 to 90
<em>This is properly represented as: [0,90]</em>
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Answer:
$160
Step-by-step explanation:
Answer:
What are the possible answer??/
Step-by-step explanation:
Answer:
The p-value would be 0.0939
Step-by-step explanation:
We can set a standard t-test for the Null Hypothesis that 
The test statistic then takes the form

with this value we then can calculate the probability that is left to the right of this value
. From theory we know that t follows a standard normal distribution. Then
which is smaller than the p-value set by Breyers of 0.10
To solve for the A or the principal amount plus interest you can use two formulas:
A = P + I
Where: P = Principal
I = Interest
or you can use
A = P (1+ rt)
Where: P = principal
r = rate in decimal
t = time in years
With your given you can use the second one, without having to use the first.
Given that the Principal amount is $222 and the rate is 12% and time is 10 years, we first need to convert your rate into decimal by dividing the value in percent by 100 which will yield 0.12.
Then now we can just input the data that you know into the formula:
A = P(1+ rt)
= $222(1 + (0.12)(10))
= $222(2.2)
= $488.40
Your A is then equal to $488.40
If you need to get the simple interest all you need to use is the first formula given:
A = P + I
for the interest you transpose the P to the side of the A and you will get:
I = A - P
= $488.40 - $222
= $266.40
$266.40 is the added interest to the principal amount.