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2 years ago

Help me plzzzzzzzzzcdvvebd

Mathematics

1 answer:

yaroslaw [1]2 years ago

7 0

copy and paste it to Jiskha Homework Helper there are connexus students there to help only use the answer from people who said that ther person answer is correct im a connexus student aswell so it work for me. Hope this helped may you mark me as brainlyest please and thank you and have a blessed day night afternoon what every it is for you

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Rates for having a manuscript typed at a certain typing service are $5 per page for the first time a page is typed and $3 per pa

Goryan [66]

Answer:

D. $680

Step By Step Explanation:

100 pages are typed. Each page coast $5 to type.

100 x 5 = 500

40 pages are revised once. It costs $3 to revise a page once.

40 x 3 = 120

10 pages are revised twice. It costs $3 to revise a page once so it will cost $6 to revise it twice

10 x 6 = 60

To find the total cost we add all the amounts together

500 + 120 + 60 = 680

The final answer is $680

6 0

3 years ago

What is 6/87 of 45638???????

lapo4ka [179]

Answer:

3,147.44828

Step-by-step explanation:

$\frac{6}{87} \: of \: 45638 \\ \\ = \frac{6}{87} \times 45638 \\ \\ = 6 \times 524.574713 \\ \\ = 3,147.44828$

5 0

2 years ago

4.4 + [4 • 1/4 + 8.6]

Delicious77 [7]

Answer: 4.4 + (4 x 1/4 + 8.6) = 14

Step-by-step explanation: Because starting inside the parenthesis, 4 times 1/4 = 1. Then 8.6 plus 1 = 9.6. Finally, 9.6 plus 4.4 which equals 14. :)

6 0

3 years ago

A marine biologist is studying the growth of a particular species of fish. She writes the following equation to show the length

inn [45]

Answer:

The original function is f(m) = 5(1.07)^m, with the m as an exponent

part A) if the final length is 9.19, we can set f(m) = 9.19 and solve for m

plugging it into a calculator, I get m = ~8.99, so a bit less than 9. therefore, a reasonable domain might be all the m values 9 or below, or m ≤ 9

part B) the y-intercept of a function is the value of the independent variable when the dependent variable = 0. the two variables in your problem are height and number of months - which one do you think is the independent one, and which one is dependent? then re-interpret "value of the independent variable when the dependent variable = 0" in terms of the actual quantities that the variables represent

part C) average rate of change from m = 1 to m = 9

f(9)−f(1)9−1

evaluate, and think about what that represents in terms of height and number of months

8 0

3 years ago

Read 2 more answers

Determine whether the set of all linear combinations of the following set of vector in R^3 is a line or a plane or all of R^3.a.

Temka [501]

Answer:

a. Line

b. Plane

c. All of R^3

Step-by-step explanation:

In order to answer this question, we need to study the linear independence between the vectors :

1 - A set of three linearly independent vectors in R^3 generates R^3.

2 - A set of two linearly independent vectors in R^3 generates a plane.

3 - A set of one vector in R^3 generates a line.

The next step to answer this question is to analyze the independence between the vectors of each set. We can do this by putting the vectors into the row of a R^(3x3) matrix. Then, by working out with the matrix we will find how many linearly independent vectors the set has :

a. Let's put the vectors into the rows of a matrix :

$\left[\begin{array}{ccc}-2&5&-3\\6&-15&9\\-10&25&-15\end{array}\right]$ ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

$\left[\begin{array}{ccc}-2&5&-3\\0&0&0\\0&0&0\end{array}\right]$

We find that the second vector is a linear combination from the first and the third one (in fact, the second vector is the first vector multiply by -3).

We also find that the third vector is a linear combination from the first and the second one (in fact, the third vector is the first vector multiply by 5).

At the end, we only have one vector in R^3 ⇒ The set of all linear combinations of the set a. is a line in R^3.

b. Again, let's put the vectors into the rows of a matrix :

$\left[\begin{array}{ccc}1&2&0\\1&1&1\\4&5&3\end{array}\right]$ ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

$\left[\begin{array}{ccc}1&1&1\\0&1&-1\\0&0&0\end{array}\right]$

We find that there are only two linearly independent vectors in the set so the set of all linear combinations of the set b. is a plane (in fact, the third vector is equivalent to the first vector plus three times the second vector).

c. Finally :

$\left[\begin{array}{ccc}0&0&3\\0&1&2\\1&1&0\end{array}\right]$ ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

$\left[\begin{array}{ccc}1&1&0\\0&1&2\\0&0&3\end{array}\right]$

The set is linearly independent so the set of all linear combination of the set c. is all of R^3.

4 0

3 years ago