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3 years ago

I really need help in this plz help if ur here

Mathematics

1 answer:

vazorg [7]3 years ago

4 0

Answer:

watch a video or use a hint.

Step-by-step explanation:

it say it.

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Write the equations for the basic absolute value equation y=|x-h|+k under the given transformations:

BlackZzzverrR [31]

Left & Right affect the h,
Up & Down affect the k,
Shrink & Stretch affect the "a" (which is in front of the absolute value expression).

1. shift 1 unit to the right and up 2 units → y = |x-1| + 2
2. shift 3 units to the left and 7 units down → y = |x + 7| - 7
3. vertical shrink by a factor of 1/3 → y = $\frac{1}{3}$ |x|
4. vertical stretch by a factor of 3 → y = 3 |x|

5 0

3 years ago

Rationalize the denominator of square root of negative 49 over open parentheses 7 minus 2 i close parentheses minus open parenth

navik [9.2K]

The answer is the option d, which is: d) $\frac{-77+21i}{130}$

The explanation for this problem is shown below:

1. Smplify the denominator and rewrite the numerator in this form:

$\frac{7i}{7-2i-4-9i} \\\frac{7i}{3-11i}$

2. Multiply the denominator and the numerator by the conjugated $(3+11i)$ and simplify the expression, as following:

$\frac{7i(3+11i)}{(3-11i)(3+11i)} \\ \frac{21i+77i^{2}}{121+9} \\ \frac{-77+21i}{130}$

3. As you can see, you obtain the expression shown in the option mentioned above.

3 0

3 years ago

Find the distance between the 2 points (6, - 4) and (2, - 7). Please show me how you found it.

Serga [27]

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 6}}\quad ,&{{ -4}})\quad 
% (c,d)
&({{ 2}}\quad ,&{{ -7}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
d=\sqrt{[2-6]^2+[-7-(-4)]^2}\implies d=\sqrt{(2-6)^2+(-7+4)^2}$

5 0

3 years ago

Compare the two functions. <img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B50%7D%20%283%29%5Ex" id="TexFormu

Anit [1.1K]

Answer:

As x increases, the rate of change of f(x) exceeds the rate of change of g(x).

Step-by-step explanation:

Hope this helps :)

5 0

3 years ago

In an experiment, a variable, position-dependent force F(x) is exerted on a block of mass 1.0kg that is moving on a horizontal s

telo118 [61]

Answer: correct option is C

The function F(x) for 0 < x < 5, the block's initial velocity, and the value of Ff.

Step-by-step explanation:

The total work done = P.E + K.E

K.E = 1/2mv^2

The speed V depends on the position:

0 < x < 5

Also, since work done = F × distance x

The workdone also depends on F(x)

The net force = 0 that is

F + fr = 0

Where fr = frictional force.

Therefore the best option for the hypothesis of work done will be;

The function F(x) for 0 < x < 5, the block's initial velocity, and the value of Ff.

6 0

3 years ago

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I really need help in this plz help if ur here ​

I really need help in this plz help if ur here