Question 3)
Given
The point (1, -5)
The slope m = -5/6
Using the point-slope form of the equation of a line
![y-y_1=m\left(x-x_1\right)](https://tex.z-dn.net/?f=y-y_1%3Dm%5Cleft%28x-x_1%5Cright%29)
where
- m is the slope of the line
In our case:
substituting the values m = -5/6 and the point (1, -5) in the point-slope form of the equation of the line
![y-y_1=m\left(x-x_1\right)](https://tex.z-dn.net/?f=y-y_1%3Dm%5Cleft%28x-x_1%5Cright%29)
![y-\left(-5\right)=-\frac{5}{6}\left(x-1\right)](https://tex.z-dn.net/?f=y-%5Cleft%28-5%5Cright%29%3D-%5Cfrac%7B5%7D%7B6%7D%5Cleft%28x-1%5Cright%29)
![y+5=-\frac{5}{6}\left(x-1\right)](https://tex.z-dn.net/?f=y%2B5%3D-%5Cfrac%7B5%7D%7B6%7D%5Cleft%28x-1%5Cright%29)
Thus, the point-slope form of the equation of the line is:
![y+5=-\frac{5}{6}\left(x-1\right)](https://tex.z-dn.net/?f=y%2B5%3D-%5Cfrac%7B5%7D%7B6%7D%5Cleft%28x-1%5Cright%29)
Question 4)
Given
The point (-1, 5)
The slope m = -7/2
In our case:
substituting the values m = -7/2 and the point (-1, 5) in the point-slope form of the equation of the line
![y-y_1=m\left(x-x_1\right)](https://tex.z-dn.net/?f=y-y_1%3Dm%5Cleft%28x-x_1%5Cright%29)
![y-5=-\frac{7}{2}\left(x-\left(-1\right)\right)](https://tex.z-dn.net/?f=y-5%3D-%5Cfrac%7B7%7D%7B2%7D%5Cleft%28x-%5Cleft%28-1%5Cright%29%5Cright%29)
![y-5=-\frac{7}{2}\left(x+1\right)](https://tex.z-dn.net/?f=y-5%3D-%5Cfrac%7B7%7D%7B2%7D%5Cleft%28x%2B1%5Cright%29)
Thus, the point-slope form of the equation of the line is:
![y-5=-\frac{7}{2}\left(x+1\right)](https://tex.z-dn.net/?f=y-5%3D-%5Cfrac%7B7%7D%7B2%7D%5Cleft%28x%2B1%5Cright%29)
Answer:
FV= 24,000*(1.07^-10)
Step-by-step explanation:
Giving the following information:
Present Value (PV)= $24,000
Decrease rate (d)= 7%
Number of periods (n)= 10 years
<u>To calculate the value of the car after 10 years, we need to use the following formula:</u>
FV= PV*(1+d)^-n
FV= 24,000*(1.07^-10)
FV= $12,200.38
Answer:
Shannon
Step-by-step explanation:
Answer:
thanks for my points back that you stole
Step-by-step explanation: