Answer:
33 1/3 L of the 40% solution, 16 2/3 L of the 25% solution
Step-by-step explanation:
Set up two equations...
Let x represent the number of Liters of the 40% solution
Let y represent the number of Liters of the 25% solution
We need 50 liters total, so
x + y = 50
and we need the 50 L to be 35% solution, so
0.4x = 0.25y = 0.35(50)
Solve the first equation for one variable...
x = 50 - y (subtract y from both sides in equation 1)
Now substitute that value into the second equation...
0.4(50 - y) + 0.25y = 17.5 (x becomes 50 - y, 0.35(50) = 17.5)
Now solve for y...
20 - 0.4y + 0.25y = 17.5
-0.15y = -2.5
y = 16.66666667
y = 16 2/3 L
So we need to plug that into the first equation to find 'x'
x + 16 2/3 = 50
x = 50 - 16 2/3
x = 33 1/3
16x +23
-16 -16
X = 7....................
Answer:
a) P value = 0.0013
b) No, it is not plausible that the silicon content of the water is no greater than it was 10 years ago
Step-by-step explanation:
The null hypothesis here is “Mean is equal to 5” while alternate hypothesis is that “Mean is greater than 5”
Given
Mean = 5, x’ = 5.4 and sigma = 1.2 and n = 85
Z = x-u’/sigma/sqrt n
Substituting the given values, we get –
Z = 3.02
A) P value = 0.0013 which is less than 0.05 and thus we will reject the null hypothesis
B) There is enough evidence to reject the null hypothesis
Answer: do 150ml*15 tubes is 2,250 ml
2,250/1000 is 2.25L (1L =1000ml is multiply by 1000)
