I know I haven't been on this app for a long time but can ya'll help me

Mathematics

1 answer:

kramer3 years ago

8 0

Answer:

2774

Step-by-step explanation:

start by multiplying 2 by 7, the answer is 14 put the 1 above the 8 in 1387 then put the 4 under the equation, similar to addition. repeat but next time when you multiply 2 by 8 add the 1 (from the previous multiplication) to the answer under and put the 1 from 17 on top of the 3. you get it?

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Factor x2 – 6x – 7.

SpyIntel [72]

You can make an cb chart. so to equal -6 you need the numbers -7, 1. so now the equation is ( x - 7 )( x + 1 ). if you want to solve it set it equal to 0 and solve.

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3 years ago

What is the distance between -2 and 5

Vlad [161]

Answer:

Step-by-step explanation:

To find distance on a number line you add and 2+5=7

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3 years ago

Can you use the SAS Postulate, the AAS Theorem, or both to prove the triangles congruent? A. either SAS or AAS B. SAS only C. AA

Harman [31]

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3 years ago

Secant jkl and jmn are drawn to circle o from an external point ,j. if jk=8,lk=4 and jm=6 what is the length of jn answer

Archy [21]

See the picture attached to better understand the problem

we know that
If two secant segments are drawn to a circle from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.
so
jl*jk=jn*jm------> jn=jl*jk/jm

we have
jk=8,lk=4 and jm=6
jl=8+4----> 12

jn=jl*jk/jm-----> jn=12*8/6----> jn=16

the answer is
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6 0

3 years ago

Can u help me ASAP. i need to know how to do it step by step

12345 [234]

Answer:

19

Step-by-step explanation:

$f(x) =4x^3-8x^2+ax+b$ has a factor $2x-1$ and

when divided by $x+2$ , remainder is 20.

To find:Remainder when divided by (x-1) ?

Solution:

$2x-1$ is a factor

$2x - 1 = 0 \Rightarrow x = \frac{1}{2}$ when we put this value of x to the function, it will become 0.

i.e.

$\Rightarrow f(\dfrac{1}{2}) =0 =4\times (\dfrac{1}2)^3-8(\dfrac{1}2)^2+\dfrac{a}{2}+b=0\\\Rightarrow \dfrac{1}{2}-2+\dfrac{a}{2}+b=0\\\Rightarrow 1-4+a+2b=0\\\Rightarrow a +2b=3 ......(1)$