3 years ago

triangle ABC has vertices at A (-12,-8) B (10,-6) and C (6,14. What is the midpoint of side AC of the triangle?

Mathematics

1 answer:

grigory [225]3 years ago

5 0

Step-by-step explanation:

midpoint of AC=(x¹+x²/2,y¹+y²/2)

=(-12+6/2,-8+14/2)

=(-6/2, 6/2)

=(-3,3)

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