triangle ABC has vertices at A (-12,-8) B (10,-6) and C (6,14. What is the midpoint of side AC of the triangle?
1 answer:
Step-by-step explanation:
midpoint of AC=(x¹+x²/2,y¹+y²/2)
=(-12+6/2,-8+14/2)
=(-6/2, 6/2)
=(-3,3)
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