Question

triangle ABC has vertices at A (-12,-8) B (10,-6) and C (6,14. What is the midpoint of side AC of the triangle?

Answer 1

Step-by-step explanation:

midpoint of AC=(x¹+x²/2,y¹+y²/2)

=(-12+6/2,-8+14/2)

=(-6/2, 6/2)

=(-3,3)