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larisa [96]
3 years ago
15

n 2018, homes in East Baton Rouge (EBR) Parish sold for an average of $239,000. You take a random sample of homes in Ascension p

arish and find that the average home sale price was $246,000 in 2018. You test the hypothesis that the mean of the home prices from Ascension parish is higher than the EBR mean. Suppose the p-value for the test is 0.045. At the 0.01 level of significance your conclusion is: (Choose the best answer)
Mathematics
1 answer:
Olenka [21]3 years ago
3 0

Answer:

Conclusion

   There is no sufficient evidence to conclude that the mean of the home prices from Ascension parish is higher than the EBR mean

Step-by-step explanation:

From the question we are told that

   The population mean for EBR is  \mu_ 1  = \$239,000

    The sample mean for Ascension parish  is \= x_2  = \$246,000

   The  p-value  is  p-value  =  0.045

     The level of significance is  \alpha = 0.01

The null hypothesis is  H_o : \mu_2  = \mu_1

The  alternative hypothesis is  H_a  :  \mu_2 > \mu_1

Here \mu_2 is the population mean for Ascension parish

   From the data given values we see that  

          p-value  >  \alpha

So we fail to reject the null hypothesis

So we conclude that there is no sufficient evidence to conclude that the mean of the home prices from Ascension parish is higher than the EBR mean

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What is the compounded interest after 3 years if you invest $10 000 and earn an interest rate of 5% per year?
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Compound Interest is the interest that is <em>compounded on a particular sum of money or investment over a given period of time.</em>

  • The interest for the first year is $1,576.25
  • The sum of money after adding the original to the interest is $11,576.25
  • The interest on the new total is $13,400.96

  • Step 1: Find the interest for the first year.

The formula is given as:

A = P(1 + r/n)^nt

P = Principal = $10,000

R = Rate = 5%

n = 1

t = 1

First, convert R as a percent to r as a decimal

r = R/100

r = 5/100

r = 0.05 rate per year,

Then solve the equation for A

A = P(1 + r/n)^nt

A = 10,000(1 + 0.05/1)^(1)(3)

A = 10,000.00(1 + 0.05)^(3)

A = $11,576.25

I = A - P

Hence:

I = $11,576.25 - $10,000.00

I (interest) = $1,576.25

  • Step 2: Add the interest to the original amount.

$10,000 +  $1,576.25

= $11,576.25

  • Step 3: Determine interest in the new total

The formula is given as:

A = P(1 + r/n)^nt

P = Principal = $11,576.25

r = 0.05 rate per year,

Then solve the equation for A

A = P(1 + r/n)^nt

A = 11,576.25(1 + 0.05/1)^(1)(3)

A = 11,576.25(1 + 0.05)^(3)

A = $13,400.96

Therefore,

  • The interest for the first year is $1,576.25
  • The sum of money after adding the original to the interest is $11,576.25
  • The interest on the new total is $13,400.96

To learn more, visit the link below:

brainly.com/question/16020930

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