Answer:
60%
Step-by-step explanation:
You can solve this problem by setting up a system of equations.
Let's say that the number of tickets bought by students in the first year is x, and the number bought by continuing students is y. From there, you can set it up like this:
0.4x+0.2y=160
x+y=500
Now, you can multiply the first equation by 5 on both sides to get:
2x+y=800
Subtracting the second equation from the first equation now yields:
x=300
y=200
Since 300 of the 500 tickets bought were from the first year students, and 300/500 is 0.6, 60% of the students who bought the ticket were first year students. Hope this helps!
Answer:
we could buy 43 party favors
Step-by-step explanation:
initially we have an amount of $380
if we already spend an amount of $272 this we have to subtract it from the total
$380 - $272 = $108
if each party favor comes out $ 2.50 and we have $ 108 we have to divide what we have by what each one comes out to know how many we can buy
$108 / $2.50 = 43.2
this means we could buy 43 party favors
Well first 9450/5=1890 then 1890/6= 315 watt hours per day
Answer:
D. LN = KM is not correct
Step-by-step explanation:
Answer:
a. $9,425.10
b. $3,707.60
Step-by-step explanation:
