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Nady [450]
3 years ago
10

PLS PLS HELP!!!!!! WILL MARK BRAINLIEST!!! :)

Mathematics
2 answers:
garri49 [273]3 years ago
6 0
Option 1 because i need points
sweet-ann [11.9K]3 years ago
4 0

Answer:

here is the best I could do...

part a: Option 1 is exponential because there is no constant. Option 2 is linear because there is a constant (+300)

part b: not sure what option 1 is, but

option 2 y= 1300+300x

part c: plug in equation for option 2 • 1300+300(20)=y

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What is an expression that equals 24 but includes an exponet
quester [9]

3 x (2)³ is an expression that's equal to 24 .

6 0
3 years ago
after five years of earning interest at an annual rate of 4% and investment has earned $1,200 in interest determine the amount o
loris [4]

Answer:

$6000

Step-by-step explanation:

$1200/5years =$240/1yr

$240=4%

:. 1%=$60

Initial investment =$60*100%=$6000

6 0
4 years ago
The average production cost for major movies is 57 million dollars and the standard deviation is 22 million dollars. Assume the
Degger [83]

Using the normal distribution, we have that:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).
  • 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.
  • 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem, the parameters are given as follows:

\mu = 57, \sigma = 22, n = 17, s = \frac{22}{\sqrt{17}} = 5.3358

Hence:

  • The distribution of X is X \approx (57,22).
  • The distribution of \mathbf{\bar{X}} is \bar{X} \approx (57, 5.3358).

The probabilities are the <u>p-value of Z when X = 58 subtracted by the p-value of Z when X = 55</u>, hence, for a single movie:

X = 58:

Z = \frac{X - \mu}{\sigma}

Z = \frac{58 - 57}{22}

Z = 0.05.

Z = 0.05 has a p-value of 0.5199.

X = 55:

Z = \frac{X - \mu}{\sigma}

Z = \frac{55 - 57}{22}

Z = -0.1.

Z = -0.1 has a p-value of 0.4602.

0.5199 - 0.4602 = 0.0597 = 5.97% probability that a single movie production cost is between 55 and 58 million dollars.

For the sample of 17 movies, we have that:

X = 58:

Z = \frac{X - \mu}{s}

Z = \frac{58 - 57}{5.3358}

Z = 0.19.

Z = 0.19 has a p-value of 0.5753.

X = 55:

Z = \frac{X - \mu}{s}

Z = \frac{55 - 57}{5.3358}

Z = -0.38.

Z = -0.38 has a p-value of 0.3520.

0.5753 - 0.3520 = 0.2233 = 22.33% probability that the average production cost of 17 movies is between 55 and 58 million dollars. Since the sample size is less than 30, assumption of normality is necessary.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

8 0
2 years ago
How many liters of water must Sharon add to 2 liters of a sugar and water solution that is 36% sugar to create a solution that i
Dahasolnce [82]

The amount of sugar x in the starting solution contributes to a 36% concentration, so we have

\dfrac x2=0.36\implies x=0.64

units of sugar in the solution.

Into this solution, Sharon wants to pour y liters of water to obtain a smaller concentration of sugar in the overall solution:

\dfrac{0.64}{2+y}=0.12\implies\dfrac{16}3=2+y\implies y=\dfrac{10}3\approx3.33

So Sharon needs to add \dfrac{10}3 liters of water to the solution to get the desired concentration.

3 0
3 years ago
Im giving 50 points
uysha [10]
-12+8x+2x=2x-8
10x-12=2x-8
8x=4
x=1/2
C
7 0
3 years ago
Read 2 more answers
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