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abruzzese [7]
3 years ago
6

Given csc(A) = 65/16 and that angle A is in Quadrant I, find the exact value of sec A in simplest radical form using a rational

denominator . Someone please help me!
Mathematics
1 answer:
IgorLugansk [536]3 years ago
8 0

Answer:

secA = \frac{65}{63}

Step-by-step explanation:

cscA = \frac{65}{16} = \frac{hypotenuse}{opposite}

This is a right triangle with hypotenuse = 65, opposite = 16 and

adjacent = \sqrt{65^2-16^2} = 63

Then

secA = \frac{hypotenuse}{adjacent} = \frac{65}{63}

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