Answer:

Step-by-step explanation:
Perimeter of the rhombus, STAR, is the sum of the length of all it's 4 sides.
The coordinates of its vertices are given as,
S(-1, 2)
T(2, 3)
A(3, 0)
R(0, -1)
Length of each side can be calculated using the distance formula given as 
Find the length of each side ST, TA, AR, RS, using the above formula by plugging in the coordinate values (x, y) of each vertices.

S(-1, 2) => (x1, y1)
T(2, 3) => (x2, y2)



T(2, 3) => (x1, y1)
A(3, 0) => (x2, y2)



A(3, 0) => (x1, y1)
R(0, -1) => (x2, y2)



R(0, -1) => (x1, y1)
S(-1, 2) => (x2, y2)




Answer:
0.6915
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 88, \sigma = 4[/ex]What is the probability that a single car of this model emits more than 86 mg/mi of NOX + NMOG?This is 1 subtracted by the pvalue of Z when X = 86. So[tex]Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=%5Cmu%20%3D%2088%2C%20%5Csigma%20%3D%204%5B%2Fex%5D%3C%2Fp%3E%3Cp%3E%3Cstrong%3EWhat%20is%20the%20probability%20that%20a%20single%20car%20of%20this%20model%20emits%20more%20than%2086%20mg%2Fmi%20of%20NOX%20%2B%20NMOG%3F%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3EThis%20is%201%20subtracted%20by%20the%20pvalue%20of%20Z%20when%20X%20%3D%2086.%20So%3C%2Fp%3E%3Cp%3E%5Btex%5DZ%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)


has a pvalue of 0.3085
1 - 0.3085 = 0.6915
The answer is 0.6915
6n + 15 = -42. If you wish to go further and find n, then subtract 15 from both sides, obtaining 6n = -57, so that n = -57/6.
Answer:
The general rule for the nth term of this sequence will be:

Step-by-step explanation:
Given the sequence
12a, 15a, 18a, 21a, 24a,...
An arithmetic sequence has a constant difference 'd' and is defined by

Here,
a₁ = 12a
computing the differences of all the adjacent terms
d = 15a-12a = 3a, d = 18a-15a=3a, d=21a-18a=3a, d=24a-21a=3a
using the nth term formula

substituting a₁ = 12a, d = 3a



Therefore, the general rule for the nth term of this sequence will be:
