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2 years ago

The ratio of rabbits to cats is 2:4 respectively. If there are

Mathematics

1 answer:

Natasha_Volkova [10]2 years ago

3 0

Answer:

there are 36 cats in one house the ratio is 1:2

Step-by-step explanation:

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Travis was attempting to make muffins to take to a neighbor. The recipe that he was working with required ¾ cup of sugar and ⅛ c

KatRina [158]

Answer:

6 cups

Step-by-step explanation:

3/4x8=

7 0

2 years ago

Solve 2x^2 + x - 4 = 0 <br> X2 +

damaskus [11]

Answer:

$\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }$

Step-by-step explanation:

Hello, please find below my work.

$2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0$

$\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0

3 years ago

A line contains the points (3, 8) and (6, 5). Write the equation of the line in slope-intercept form. Use no spaces in your equa

Artyom0805 [142]

5-8
------ =-3/3=1
6-3
y=1x+b

4 0

2 years ago

Read 2 more answers

Which value is the best estimate for 6√10

garik1379 [7]

Answer:

18.97366596

Step-by-step explanation:

round however manu you need too

3 0

3 years ago

A company finds that the rate at which the quantity of a product that consumers demand changes with respect to price is given by

d1i1m1o1n [39]

Answer:

q = 5000/x + 6

Step-by-step explanation:

D´= dq/dx = - 5000/x²

dq = -( 5000/x²)*dx

Integrating on both sides of the equation we get:

q = -5000*∫ 1/x²) *dx

q = 5000/x + K in this equation x is the price per unit and q demanded quantity and K integration constant

If when 1006 units are demanded when the rice is 5 then

x = 5 and q = 1006

1006 = 5000/5 +K

1006 - 1000 = K

K = 6

Then the demand function is:

q = 5000/x + 6

3 0

2 years ago