A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer:
sinx
Step-by-step explanation:
hello :
note :
for all x in ℝ : 1) sin(x+2π) = sinx 2) sin(π-x) = sinx
in this exercice :
3π - x = 2π+(π - x)
sin(3π - x) = sin(2π +(π - x)) =sin(π-x) = sinx
Answer:
x=6
Step-by-step explanation:
since y=5x/2-7, and y=4x/3
so 5x/2-7=4x/3
5x/2-4x/3= 7
15x-8x/6=7
7x/6=7
x= 7*6/7= 6
Which equation? Sorry I don’t see one
Answer:
no
Step-by-step explanation:
