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Volgvan
3 years ago
9

I’ve never understood this, please help!

Mathematics
1 answer:
vlabodo [156]3 years ago
7 0

Answer:

-80

Step-by-step explanation:

So basically what we need to do is find the value of x that satisfies the equation.

When I mean satisfy, I basically mean a value of x that makes one side of the equals sign equal to the other side of the equals sign.

So in this case, we need -6 = -6.

To find this lets solve the equaion step by step:

-6=x/8+4

So first off, you always want to get the variable on one side, and the number on the other.

This means you want to subtract the 4 from both sides, leaving x/8:

-6=x/8+4

-4       -4

-10=x/8

Whenever x is not 1x, you have to divide or multiply to get it equal to 1x.

If this is a bit confusing, here is an example:

100=10x

We need 1x, but above is 10x. The reason why we want 1x is because it is the lowest ratio, and most accurate x value.

You can think of it like a 1 dollar bill. Its easier and better to use than per say a 3 dollar bill.

So in the example above you would divide by 10, since 10x/10 would equal 1x.

Remember the rule however, that what you do on one side you must do on the other. This emans you would divide both sides by 10:

100/10 =10x/10

=

10=1x

We have in our equation:

-10=x/8

Our x is lower than 1. It x/8. Whenever we have a value of x greater than 1, we divide, like we did in the example. However here, it is below x. So we multiply.

In this case we multiply by 8, since its x/8:

-10 * 8 = x/8 * 8

=

-80=x

So x is equal to -80.

I hope you understand it better now :D

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A chemical company claims that its new additives increases gasmileage. As a pilot study, the company send 36 cars fueled withthe
8090 [49]

Answer:

Check Explanation

Step-by-step explanation:

Normally the mean mileage for the 36 cars without the additive is 25 miles per gallon of gas with a standard deviation of 2.4 mpg

With the additive, the mileage improves to 25.8 mpg.

The sample mean without additive is 25 mpg

The standard deviation of the distribution of sample means for mileage without additive = σₓ = (σ/√n)

where σ = normal standard deviation = 2.4 mpg

n = Sample size = 36

σₓ = (σ/√n) = (2.4/√36)

σₓ = 0.4 mpg

So, a normal distribution of sample means for mileage without gas should have 95% of the possible values between 2 standard deviations of the mean. That is, within 24.2 mpg and 25.8 mpg.

Therefore, a mileage of 25.8 mpg with the additive added cannot point at a significant effectiveness of the additive as this data has shown that 25.8 mpg is within the possible values for sample means for mileage without the use of additives.

Although, it does point at an improved performance with the additive because a sample mean of 25.8 mpg without the additive is on the outskirts of possible sample mean values.

Hope this Helps!!!

3 0
4 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B22%7D%20%2B%20%5Cfrac%7B3%7D%7B22%7D%20" id="TexFormula1" title="\frac{8}{22}
Vaselesa [24]

Answer:

8/22+3/22=11/22

Step-by-step explanation:

8+3=11

3 0
3 years ago
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The manufacturer of an airport baggage scanning machine claims it can handle an average of 553 bags per hour. (a-1) At α = .05 i
timurjin [86]

Answer:

H1 : μ < 553. Reject H1 if tcalc > –1.753.

There is not enough evidence to reject the manufacturer’s claim.

Step-by-step explanation:

We are given that the manufacturer of an airport baggage scanning machine claims it can handle an average of 553 bags per hour.

A sample of 16 randomly chosen hours with a mean of 533 and a standard deviation of 47 is given.

Let \mu = <u><em>average bags that an airport baggage scanning machine can handle.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq 553 bags     {means that the manufacturer’s claim is not overstated}

Alternate Hypothesis, H_0 : \mu < 553 bags     {means that the manufacturer’s claim is overstated}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean = 533 bags

            s = sample standard deviation = 47

            n = sample of hours = 16

So, <u><em>the test statistics</em></u>  =  \frac{533-553}{\frac{47}{\sqrt{16} } }  ~ t_1_5

                                     =  -1.702

The value of t test statistics is -1.702.

<u>Now, at 0.05 significance level the t table gives critical value of -1.753 at 15 degree of freedom for left-tailed test.</u>

Since our test statistic is more than the critical value of t as -1.702 > -1.753, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the manufacturer’s claim is not overstated and an airport baggage scanning machine can handle an average of 553 bags per hour.

5 0
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Hey, can someone please explain to me this problem. I’m not understanding Segment Addition Postulate. Sorry for the bad handwrit
loris [4]

The measure of the segment DF is 2 2/3

<h3>Segment  Addition postulate</h3>

The segment addition postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

A line is a distance between two points. From the given line;

DF = F - D

Given the following

F = -1 1/3
D = -4

Substitute

DF = -1 1/3 - (-4)

DF = 4 - 4/3

DF = 8/3

DF =2 2/3

Hence the measure of the segment DF is 2 2/3

Learn more on Segment  Addition postulate here: brainly.com/question/2134445

#SPJ1

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Ilya [14]

perpendicular means negative reciprocal so it would be -1/3

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3 years ago
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