Answer:
Likely
First option is correct.
Step-by-step explanation:
The probability for occurring the event = 95% = 0.95
Let us understand different types of events:-
- Certain events: If the probability of occurring an even is 1, then it is a certain event.
- Impossible events: If the probability of occurring an even is 0, then it is a impossible event.
- Likely events: If the probability of occurring an even is close to 1, then it is a likely event.
- Unlikely events: If the probability of occurring an even is close to 0, then it is a unlikely event.
Now, the probability for occurring the event = 95% = 0.95, which is close to 1.
Hence, we can conclude that the event is likely.
First option is correct.
Answer: LCM = 720, GCF = 5 Please consider Brainliest.
Step-by-step explanation:
Find the least multiple of all three numbers, it should be 720. Find the Greatest factor, which should work. But remember, 15 doesn't work because 80 doesn't have 15 as a factor.
Answer:
2
Step-by-step explanation:
2x(5+4)=(_x5)+(_x4)
lets start with 2x(5+4)
(5+4)=9
so we are left with 2x9
2x9=18
so now we have 18=(_x5)+(_x4)
lets try 2 for the blank spaces
18=(2x5)+(2x4)
2x5=10
2x4=8
10+8=18
2x(5+4)=(2x5)+(2x4)
It worked! Hope this helps :)
Answer:
a. 0.12109
b. 0.0001668
c .0.9726
d. 0.01038
e. 0.01211
f. 0.000001731
Step-by-step explanation:
Sample size = 580
Defective units = 8
Number of picks = 2
a) If the first container is defective, there 7 defective containers left in a population of 579. The probability of selecting a defective one is:
![P=\frac{7}{579}=0.121](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B7%7D%7B579%7D%3D0.121)
b) The probability that both are defective is given by:
![P=\frac{8}{580}*\frac{7}{579}= 0.000167](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B8%7D%7B580%7D%2A%5Cfrac%7B7%7D%7B579%7D%3D%200.000167)
c) The probability that both are acceptable is given by:
![P=\frac{580-8}{580}*\frac{579-8}{579}= 0.9726](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B580-8%7D%7B580%7D%2A%5Cfrac%7B579-8%7D%7B579%7D%3D%200.9726)
d) In this case, two defective units were removed from the batch, the probability that the third is also defective is:
![P=\frac{6}{578}}= 0.0104](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B6%7D%7B578%7D%7D%3D%200.0104)
e) In this case, one acceptable and one defective unit were removed from the batch, the probability that the third is also defective is:
![P=\frac{7}{578}= 0.01211](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B7%7D%7B578%7D%3D%200.01211)
f) The probability that all three are defective is given by:
![P=\frac{8}{580}*\frac{7}{579}*\frac{6}{578} = 0.000001731](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B8%7D%7B580%7D%2A%5Cfrac%7B7%7D%7B579%7D%2A%5Cfrac%7B6%7D%7B578%7D%20%3D%200.000001731)
Answer:
$4.57. Hope this helps :)
Step-by-step explanation:
20+5=25
then you do
25-3.67= $21.33
you then divide that by the number of pounds she bought.
21.33/4= 5.3325
round that to the hundreths place and you get $5.33
so she paid $5.33 for a pound