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OLEGan [10]
3 years ago
10

Help help please !!!!!! Thank u ❤️

Mathematics
1 answer:
hammer [34]3 years ago
8 0

Answer:

Middle bar

Step-by-step explanation:

6 + 4 = 10

10 + 5 = 15

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What is the domain of the function y = 2 VX-5?
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<em>R</em>

Step-by-step explanation:

All linear functions have a range and domain of R [ALL REAL NUMBERS].

I am joyous to assist you anytime.

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Simplify the following expression <br>9/20 + 5/12​
Artyom0805 [142]

<em>9/20+5/12=14/32/2 equals a over all 7/16</em>

4 0
3 years ago
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A map uses a scale of 3/4 in = 80 miles. If two buildings are 60 miles apart in real life, how far apart would they be drawn on
Alla [95]

Given:

The scale of a map is \dfrac{3}{4}\ in=80\ miles.

The distance between two buildings is 60 miles.

To find:

The distance between the given building on the map.

Solution:

We have,

\dfrac{3}{4}\ in=80\ miles

It means, 80 miles in real life = \dfrac{3}{4}\ in on the map.

1 mile in real life = \dfrac{3}{4\times 80}\ in on the map.

60 mile in real life = \dfrac{3\times 60}{4\times 80}\ in on the map.

                              = \dfrac{180}{320}\ in on the map.

                              = \dfrac{9}{16}\ in on the map.

Therefore, the buildings are \dfrac{9}{16}\ in apart on the map.

7 0
3 years ago
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3 years ago
Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $10,
Andreyy89

Answer:

1) the planning value for the population standard deviation is 10,000

2)

a) Margin of error E = 500, n = 1536.64 ≈ 1537

b) Margin of error E = 200, n = 9604

c) Margin of error E = 100, n = 38416

3)

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

Step-by-step explanation:

Given the data in the question;

1) Planning Value for the population standard deviation will be;

⇒ ( 50,000 - 10,000 ) / 4

= 40,000 / 4

σ = 10,000

Hence, the planning value for the population standard deviation is 10,000

2) how large a sample should be taken if the desired margin of error is;

we know that, n = [ (z_{\alpha /2 × σ ) / E ]²

given that confidence level = 95%, so z_{\alpha /2  = 1.96

Now,

a) Margin of error E = 500

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 500 ]²

n = [ 19600 / 500 ]²

n = 1536.64 ≈ 1537

b) Margin of error E = 200

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 200 ]²

n = [ 19600 / 200 ]²

n = 9604

c)  Margin of error E = 100

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 100 ]²

n = [ 19600 / 100 ]²

n = 38416

3) Would you recommend trying to obtain the $100 margin of error?

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

7 0
2 years ago
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