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Nuetrik [128]
3 years ago
6

2 less than six times a number. er:

Mathematics
1 answer:
andreev551 [17]3 years ago
7 0
6x-3 this ? I don’t how you want it but hope it’s this ?
You might be interested in
Plz help what is 7x+14 divided by 7
Luba_88 [7]

Answer:

x + 2

Step-by-step explanation:

7x+14 divided by 7

\frac{7}{7} x + \frac{14}{7} \\= 1x +2\\= x + 2

Hope this helps !

4 0
3 years ago
Joy wants to create a box with a volume of 8 cubic units. which dimensions would work
N76 [4]

Answer:

The dimensions of the box is 2 units.

Step-by-step explanation:

Volume of cube, V = 8 cubic units

Let the length of the side is a.

So,

The volume of the cube is

V = a^3\\\\8 = a^3\\\\a = 2 units

So, the dimensions of the box is 2 units.  

4 0
3 years ago
Which set of side will make a triangle
Ostrovityanka [42]

Answer:

d.10cm,5cm,9cm

Step-by-step explanation:

In a triangle, the length of each side must be between the difference and the sum of the lengths of the other sides.

a. 1 + 1 = 2; 2 < 3     Answer: no

b. 2 + 3 = 5; 5 = 5     Answer: no

c. 10 - 3 = 7; 7 > 4      Answer: no

d. 10 + 5 > 9

5 + 9 > 10

10 + 9 > 5

10 - 5 < 9

10 - 9 < 5

9 - 5 <10

Answer: yes

6 0
3 years ago
Can someone help me with it? click on the photo to see it in full screen
dsp73

Answer:

Angie will need to save $2.50 for 8 more weeks to get $50

Step-by-step explanation:

Angie has already saved $30

12(2.5)=30

So since she needs $20 more you divide 20 by 2.5 and you get your answer.

20/2.5=8 weeks

6 0
4 years ago
Use fundamental theorem of calculus to find derivative of the function LOOK AT PHOTO
kykrilka [37]

Let c > 0. Then split the integral at t = c to write

f(x) = \displaystyle \int_{\ln(x)}^{\frac1x} (t + \sin(t)) \, dt = \int_c^{\frac1x} (t + \sin(t)) \, dt - \int_c^{\ln(x)} (t + \sin(t)) \, dt

By the FTC, the derivative is

\displaystyle \frac{df}{dx} = \left(\frac1x + \sin\left(\frac1x\right)\right) \frac{d}{dx}\left[\frac1x\right] - (\ln(x) + \sin(\ln(x))) \frac{d}{dx}\left[\ln(x)\right] \\\\ = -\frac1{x^2} \left(\frac1x + \sin\left(\frac1x\right)\right) - \frac1x (\ln(x) + \sin(\ln(x))) \\\\ = -\frac1{x^3} - \frac{\sin\left(\frac1x\right)}{x^2} - \frac{\ln(x)}x - \frac{\sin(\ln(x))}x \\\\ = -\frac{1 + x\sin\left(\frac1x\right) + x^2\ln(x) + x^2 \sin(\ln(x))}{x^3}

8 0
3 years ago
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