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olga2289 [7]
3 years ago
6

Find the 7th term of the geometric progression which begins -6250, 1250, -250....

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
5 0

Answer:

a(7) = -0.4

Step-by-step explanation:

The general formula for a geometric progression is a(n) = a(1)*r^(n - 1), where r is the common ratio.  In this problem, a(1) = -6250.  To find r, we divide 1250 (the 2nd term) by -6250 (the 1st term), obtaining r = -0.2.

Then the formula for THIS geometric progression is

a(n) = -6250*(-0.2)^(n - 1).

Thus, the 7th term of THIS progression is

a(7) = -6250*(-0.2)^(7 - 1), or -6250*(-0.2)^6, or -0.4

kvasek [131]3 years ago
4 0

Answer:

a₇ = - \frac{2}{5}

Step-by-step explanation:

The nth term of a geometric progression is

a_{n} = a₁ r^{n-1}

where a₁ is the first term and r the common ratio

Here a₁ = - 6250 and r = \frac{a_{2} }{a_{1} } = \frac{1250}{-6250} = - \frac{1}{5} , then

a₇ = - 6250 × (-\frac{1}{5}) ^{6} = - 6250 × \frac{1}{15625} = \frac{-6250}{15625} = - \frac{2}{5}

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andreyandreev [35.5K]

Answer:

1) 3

2) 30

Step-by-step explanation:

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For the number 15, we can get <u>3</u> x 5 = 15.

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Four less than the quotient of a number x and 5
pochemuha
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