The solution of y=
given as:
x: 0 1 2 3
y: 0 3 10 21
<h3>What is Linear Equation?</h3>
A linear equation is an algebraic equation of the form y=mx+b. involving only a constant and a first-order (linear) term, where m is the slope and b is the y-intercept.
Given function is:
y= 
For finding the solution of above expression, take value of x and solve for y.
y= 2(0)+0
y=0
y= 
y=
y= 
The required table is:
x: 0 1 2 3
y: 0 3 10 21
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Answers:
- All values of t must be positive
- A viable solution is (10, 50)
- All values of t must be positive.
EXPLANATION
t, temperature (in Fahrenheit) is dependent on c
c is the number of cricket chirps heard in 14 seconds
Therefore, all values of c must be positive integers
If all values of c must be positive integers
Then all values of t must also be positive integers
- A viable solution is (10, 50).
EXPLANATION
t = c + 40
Since 10 is a positive integer, it is a possible value for c
If c = 10
t = 10 + 10
t = 50
Therefore a viable solution is (10, 50)
EXPLANATION FOR WHY OTHER OPTIONS ARE WRONG:
- The graph is continuous.
This is WRONG because this function only allows the values of c to be only certain points in the interval (only positive integers). Therefore, it is a discrete function.
- A viable solution is (–2, 38)
This is WRONG because the -2 is a negative integer, and the value of c cannot be a negative integer.
- A viable solution is (0.5, 40.5)
This is WRONG because 0.5 is not an integer, and all values of t must also be positive integers.
Answer:
This is what I put:
Step-by-step explanation:
Answer:
21.89
Step-by-step explanation:
add and subtract
Answer:
Not a factor
Step-by-step explanation:
We can use Factor Theorem to answer this question. According to this theorem, in order to find if (x - a) is a factor of a polynomial f(x), calculate f(a). If f(a) comes out to be equal to zero, this will mean that (x-a) is factor of f(x).
Here, the expression we have is (x + 7), so we need to find f(-7) in order to check if (x+7) is a factor of f(x) or not

Substituting x = -7, we get:

Since f(-7) ≠ 0, (x + 7) is not a factor of the polynomial f(x)