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Elina [12.6K]
2 years ago
7

Please help this is the last problem I need

Mathematics
1 answer:
tangare [24]2 years ago
8 0

Answer:

sin 54 = \frac{x}{14}

Step-by-step explanation:

sine = \frac{opposite}{hypotenuse}

Side z is the adjacent, since it is next to the angle you are solving for.

Side x is the opposite, since it is opposite the angle you are solving for.

The side measuring 14 is the hypotenuse, since it is across from the right angle.

sin 54 = \frac{x}{14}

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Tamara gets paid an annual salary of $48,000 and earns 4% commission on all sales she makes. If Tamara wants to make $6,000 this
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7 0
3 years ago
Can someone please help me solve these two problems and explain them to me? About the one with proportions though... I've always
NeTakaya

Answers:

A) -\frac{11}{4}

C) m_{1}=\frac{Fr^{2}}{G m_{2}}

Step-by-step explanation:

<u>Part 1:</u>

We have the followig equation:

\frac{x-1}{3}-\frac{x+4}{5}=\frac{4x-1}{8}

Calculating the least common multiple (l.c.m) in the denominator in the left side of the equation, being l.c.m=15:

\frac{5(x-1)-3(x+4)}{15}=\frac{4x-1}{8}

Solving for the left part of the equation:

\frac{2x-17}{15}=\frac{4x-1}{8}

Operating with cross product:

8(2x-17)=15(4x-1)

Applying the distributive property:

16x-136=60x-15

Isolating x:

x=-\frac{121}{44}

Dividing numerator and denominator by 11:

x=-\frac{11}{4} Hence, the correct option is A

<u>Part 2:</u>

We have the followig equation:

F=\frac{G m_{1} m_{2}}{r^{2}}

Operating with cross product:

Fr^{2}=G m_{1} m_{2}

Isolating m_{1}:

m_{1}=\frac{Fr^{2}}{G m_{2}} Hence, the correct option is C

5 0
3 years ago
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