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Sholpan [36]
3 years ago
9

Simplify using distributive property 4(z+2)+2(3-z)

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
5 0

Answer:

2z+14

Step-by-step explanation:

you multiply

4*z   =4z

4*2   =8

and then you multiply

2*3=6

2*-z=-2z

the answer is 2z+14

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Plz help me with this problem
Evgen [1.6K]
First we rearrange by using the definition of between.
AB=x+10, BC=x+14, AC=22
Given that AB+BC=AC, we can solve for X
(X+10)+(X+14)=22
X+10+X+14=22
2X+24=22
2X+24-24=22-24
2X=-2
2X/2=-2/2
X= -1
3 0
3 years ago
Why is 3/4 greater thab 11/16 how can i be sure
Delicious77 [7]
You can make them have the same denominator and then compare

( \frac{3}{4}) ( \frac{16}{16}) =  \frac{48}{64}

(\frac{11}{16})( \frac{4}{4}) =  \frac{44}{64}

so as you can see, \frac{3}{4} is \frac{4}{64} bigger than  \frac{11}{16}
5 0
3 years ago
Which function has a domain of (-∞, ∞) and a range of (-3, ∞)?
shtirl [24]

Answer:

Step-by-step explanation:

The function that will have the domain (\infty, \infty) and a range of (-3, \infty) is the

function in option d.) f(x) = e^x - 3

5 0
3 years ago
Maria has 2 dogs. Her friend bought her h more dogs. Write an expression that show how many dogs Maria has now.
AVprozaik [17]

Answer:

2+h

Step-by-step explanation:

7 0
3 years ago
Solve the following system by any method -8x-8y=0 -8x+2y=-20
iVinArrow [24]
                     \fbox{Solution by using Matrix} 

\text{Linear Equation} = -8x-8y=0 , -8x+2y=-20

\text{Rewrite the linear equations above as a matrix} 

\left[\begin{array}{ccc}8&-8&0\\-8&2&-20\\\end{array}\right] 

\text{Apply to Row2 : Row2 + Row1} 

\left[\begin{array}{ccc}8&-8&0\\-8&-6&-20\\\end{array}\right] 

\text{ Simplify rows} 

\left[\begin{array}{ccc}8&-8&0\\0&1&10/3\\\end{array}\right] 

\text{Note: The matrix is now in echelon form.}\text{The steps below are for back substitution.} 

\text{Apply to Row1 : Row1 + 8 Row2} 

\left[\begin{array}{ccc}8&0&80/30\\0&1&10/3\\\end{array}\right] 

\text{ Simplify rows}  

\left[\begin{array}{ccc}1&0&10/3\\0&1&10/3\\\end{array}\right] 

\text{Therefore, the solution is} 

x= \dfrac{10}{3} \ \text{and} \ \ y=\dfrac{10}{3}
7 0
3 years ago
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