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SOVA2 [1]
4 years ago
14

40/6 what is the closest whole number?

Mathematics
2 answers:
Anvisha [2.4K]4 years ago
6 0
ANSWER: 7

EXPLANATION/EQUATION:

40 <span>÷ 6 = 6.666...
</span><span>≈ 7
</span>
After you divide, you are left with 6.666... When rounding to the nearest whole number, the number needs to be rounded based on the tenth; in this case, the tenth is represented by a 6. 6 is closer to 10 than 1, so you round up. Therefore, the answer is 7.
shusha [124]4 years ago
4 0
7, because 40/6 is 6.6666... and you have to round up 6, so your answer is 7.
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A nationwide sample of influential Republicans and Democrats was asked as a part of a comprehensive survey whether they favored
pickupchik [31]

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We conclude that there is an equal or larger proportion of Republicans in favor of lowering the standards.

Step-by-step explanation:

<u>The complete question is</u>: A nationwide sample of influential Republicans and Democrats was asked as a part of a comprehensive survey whether they favored lowering environmental standards so that high-sulfur coal could be burned in coal-fired power plants. The results were:

Number sampled: 1,000 (republican) , 800 (democrats)

Number in favor: 200 (republican) , 168 (democrats)

At the 0.02 level of significance, can we conclude that there is a larger proportion of Democrats in favor of lowering the standards? Determine the p-value.

Let p_1 = <u><em>proportion of Republicans in favor of lowering the standards</em></u>.

p_2 = <u><em>proportion of Democrats in favor of lowering the standards</em></u>.

SO, Null Hypothesis, H_0 : p_1 \geq p_2     {means that there is an equal or larger proportion of Republicans in favor of lowering the standards}

Alternate Hypothesis, H_A : p_1 < p_2     {means that there is a larger proportion of Democrats in favor of lowering the standards}

The test statistics that would be used here <u>Two-sample z-test for</u> <u>proportions</u>;

                         T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~ N(0,1)

where, \hat p_1 = sample proportion of Republicans in favor of lowering the standards = \frac{200}{1000} = 0.20

\hat p_2 = sample proportion of Democrats in favor of lowering the standards = \frac{168}{800} = 0.21

n_1 = sample of Republicans = 1000

n_2 = sample of Democrats = 800

So, <u><em>the test statistics</em></u>  =  \frac{(0.20-0.21)-(0)}{\sqrt{\frac{0.20(1-0.20)}{1000}+\frac{0.21(1-0.21)}{800} } }

                                     =  -0.52

The value of z test statistics is -0.52.

<u>Now, P-value of the test statistics is given by the following formula; </u>

            P-value = P(Z < -0.52) = 1 - P(Z \leq 0.52)

                          = 1 - 0.6985 = 0.3015

Now, at 0.02 significance level, the z table gives a critical value of -2.054 for left-tailed test.

Since our test statistic is more than the critical value of z as -0.52 > -2.054, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <em><u>we fail to reject our null hypothesis</u></em>.

Therefore, we conclude that there is an equal or larger proportion of Republicans in favor of lowering the standards.

7 0
3 years ago
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