Answer:
a) 
b) 
c) 
Step-by-step explanation:
<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.
This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.
Then write the polynomial in factored form.

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.
<u>For question b, do the same procedure</u>.
Degree: 3
Zeros: -5/2, 4/5, 6.
The factors are

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<u>Finally for the question c we have</u>
Degree: 5
Zeros: -3, 1, 4, -1
Multiplicity 2 in -1

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Let
x-------> the first number
y------> the second number
we know that


equation 

equation 
substitute equation 1 in equation 2

using a graph tool-----> to resolve the second order equation
see the attached figure
the solution is

Answer:
i think its b but im not sure
Step-by-step explanation:
Answer:
In order, your numbers are
22, 45, 75, 89, 89, 95, 100
The median is the number that is in the middle numbers of all your numbers. The median is 89, since it is in the very middle.
The mean is all your numbers added together and then divided by how ever many numbers you have. 22 + 45 + 75 + 89 + 89 + 95 + 100 = 515. Since you have 7 numbers, you would divide 515 by 7, which equals 73.5. The mean is 73.5.
The mode is the number that has the most numbers(not sure how to word it) Since 89 has two of the numbers, and no other numbers have duplicates, your mode is 89.