Answer:
The percentage of the bag that should have popped 96 kernels or more is 2.1%.
Step-by-step explanation:
The random variable <em>X</em> can be defined as the number of popcorn kernels that popped out of a mini bag.
The mean is, <em>μ</em> = 72 and the standard deviation is, <em>σ</em> = 12.
Assume that the population of the number of popcorn kernels that popped out of a mini bag follows a Normal distribution.
Compute the probability that a bag popped 96 kernels or more as follows:
Apply continuity correction:


*Use a <em>z</em>-table.
The probability that a bag popped 96 kernels or more is 0.021.
The percentage is, 0.021 × 100 = 2.1%.
Thus, the percentage of the bag that should have popped 96 kernels or more is 2.1%.
Answer:
because all the fans have left
Step-by-step explanation:
Answer: 1/3
Step-by-step explanation:
lol hope i helped:)
Answer:
He bought 7 lightbulbs.
Step-by-step explanation:
37.19 - 3.73 = 33.46
33.46/4.78=7
Answer:
Give me brainliest first and i will give u the answer
Step-by-step explanation: