Answer:
<u><em>Measure of angle A is 27 7/9 degrees.</em></u>
Step-by-step explanation:
Lets call measure of angle A is <em><u>X-10</u></em>
Lets call measure of angle B is X
Lets call measure of angle D is 2.5X+20
We know that the sum of triangles add up to 180 degrees
X+X-10+2.5X+20=180
X=37 7/9
So measure of angle A is 27 7/9 degrees.
I hope this is right. :)
The angles opposite equal sides are also equal. The sum of angles in a triangle is 180. So 2x + 27 + 2x + 27 + 3x + 28 = 180.
7x + 82 = 180
7x = 98
x = 14
Now plug x into each angle to find their measures.
Answer:
all the would need water becouse water is the main reason to get live
Find the reciprocal of the second fraction (flip numerator and denominator's spots) and multiply the two fractions.
Answer:
After 11 years the value of the investment reaches $1500.00
.
Step-by-step explanation:
The formula used for finding time (when the value reaches certain amount) is:
![A= P(1+\frac{r}{n})^{nt}](https://tex.z-dn.net/?f=A%3D%20P%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D)
where A= Future VAlue
P= Principal Value
r= rate of interest (in decimal)
n= no of times investment is compounded
t= time
Putting the values given and finding Time t,
A= $1500
P= $1200
r= 2% or 0.02
n= 4 (compound quarterly)
![A= P(1+\frac{r}{n})^{nt}](https://tex.z-dn.net/?f=A%3D%20P%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D)
![1500= 1200(1+\frac{0.02}{4})^{4t}](https://tex.z-dn.net/?f=1500%3D%201200%281%2B%5Cfrac%7B0.02%7D%7B4%7D%29%5E%7B4t%7D)
Dividing both sides by 1200 and solving 0.02/4 = 0.005
![1.25= (1+0.005)^{4t}](https://tex.z-dn.net/?f=1.25%3D%20%281%2B0.005%29%5E%7B4t%7D)
![1.25= (1.005)^{4t}](https://tex.z-dn.net/?f=1.25%3D%20%281.005%29%5E%7B4t%7D)
Since t is in power we take the logarithm ln on both sides.
The rule of logarithm says that the exponent can be multiplied with the base when taking log
![\ln1.25=ln( 1.005)^{4t}\\\ln1.25=4t * ln( 1.005)\\0.22 = 4t * 0.005\\Solving\,\,\\\frac{0.22}{4*0.005} = t\\=> t= 11\, years](https://tex.z-dn.net/?f=%5Cln1.25%3Dln%28%201.005%29%5E%7B4t%7D%5C%5C%5Cln1.25%3D4t%20%2A%20ln%28%201.005%29%5C%5C0.22%20%3D%204t%20%2A%200.005%5C%5CSolving%5C%2C%5C%2C%5C%5C%5Cfrac%7B0.22%7D%7B4%2A0.005%7D%20%3D%20t%5C%5C%3D%3E%20t%3D%2011%5C%2C%20years)