It is not possible for 120 kids and 20 adults to go on the trip, but 120 students can go with a maximum of 12 adults so the expense of the trip can fall in the school's budget.
We know that tickets of the zoo cost $15 for adults and $11 for children.
The equation representing the budget for the trip is 15x + 11y = 1500.
where, x is the no. of adults and y is the number of children that are travelling.
If x = 20 and y = 120 then,
15(20)+11(120)=300+1320=1620 which is out of the budget of the school.
If 120 students want to go to school then, no. of adults that can travel can be determined as
15 x + 11 (120 )<= 1500
15x <=1500-1320
15x<=180
x <=12
Therefore, we can conclude that 120 students and 20 adults cannot travel for the trip but 120 students can travel with a maximum of 12 adults among with them as it will cost school the trip in the budget.
Learn more about Linear Inequality here brainly.com/question/11897796
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Answer:
unknown
Step-by-step explanation:
I am sorry but part of your question is missing
Answer:
Step-by-step explanation:
(2n - 3)(5n + 6) = 2n*(5n + 6) -3*(5n +6)
=2n*5n + 2n*6 -3*5n + (-3)*6
=10n² + 12n - 15n - 18
= 10n² -3n - 18
If you mean y= -3x*2.5 then yes, it's linear.
Answer:
274 parents
Step-by-step explanation:
38 tables times 12 per table
38*12=456
456-182=274
