Answer:
Li
Explanation:
The phenomenon of wave particle duality was well established by Louis deBroglie. The wavelength associated with matter waves was related to its mass and velocity as shown below;
λ= h/mv
Where;
λ= wavelength of matter waves
m= mass of the particle
v= velocity of the particle
This implies that if the velocities of all particles are the same, the wavelength of matter waves will now depend on the mass of the particle. Hence; the wavelength of a matter wave associated with a particle is inversely proportional to the magnitude of the particle's linear momentum. The longest wavelength will then be obtained from the smallest mass of matter. Hence lithium which has the smallest mass will exhibit the longest DeBroglie wavelength
Answer:
1) The power needed to process 50 ton/hr is 135.4 HP.
2) The void fraction of the bed is 0.37.
Explanation:
1) For this type of milling operations, we can estimate the power needed for an operation according to the work index (Ei), the passing size of the circuit feed (F80) and the passing size of the product (P80).
We assume the units of Ei are kWh/t.
The equation that relates this parameters and the power is (size of particles in μm):
![W=Ei*(\frac{10}{\sqrt{P80}} -\frac{10}{\sqrt{F80}} )\\\\W=9.45*(\frac{10}{\sqrt{3175\mu m}} -\frac{10}{\sqrt{76200mm}} )\\\\\\W=9.45*(0.1774+0.0362)=2.019 kWh/t](https://tex.z-dn.net/?f=W%3DEi%2A%28%5Cfrac%7B10%7D%7B%5Csqrt%7BP80%7D%7D%20-%5Cfrac%7B10%7D%7B%5Csqrt%7BF80%7D%7D%20%29%5C%5C%5C%5CW%3D9.45%2A%28%5Cfrac%7B10%7D%7B%5Csqrt%7B3175%5Cmu%20m%7D%7D%20-%5Cfrac%7B10%7D%7B%5Csqrt%7B76200mm%7D%7D%20%29%5C%5C%5C%5C%5C%5CW%3D9.45%2A%280.1774%2B0.0362%29%3D2.019%20kWh%2Ft)
The power needed to process 50 ton/hor is
![P=2.0194\frac{kWh}{Ton}*\frac{50Ton}{h}*\frac{1.341HP}{1kW}= 135.4 \, HP](https://tex.z-dn.net/?f=P%3D2.0194%5Cfrac%7BkWh%7D%7BTon%7D%2A%5Cfrac%7B50Ton%7D%7Bh%7D%2A%5Cfrac%7B1.341HP%7D%7B1kW%7D%3D%20%20%20135.4%20%5C%2C%20HP)
2) The density of the packed bed can be expressed as
![\rho=f_v*\rho_v+f_s*\rho_s](https://tex.z-dn.net/?f=%5Crho%3Df_v%2A%5Crho_v%2Bf_s%2A%5Crho_s)
being f the fraction and ρ the density of every fraction. We know that the density of the void is 0 (ρv=0) and that fv=1-fs (the sum of the fractions ois equal to the total space).
Then we can rearrange
![\rho=f_v*\rho_v+f_s*\rho_s\\\\\rho=f_v*0+(1-f_v)*\rho_s\\\\\rho/\rho_s=1-f_v\\\\f_v=1-\rho/\rho_s=1-990/1570=1-0.63=0.37](https://tex.z-dn.net/?f=%5Crho%3Df_v%2A%5Crho_v%2Bf_s%2A%5Crho_s%5C%5C%5C%5C%5Crho%3Df_v%2A0%2B%281-f_v%29%2A%5Crho_s%5C%5C%5C%5C%5Crho%2F%5Crho_s%3D1-f_v%5C%5C%5C%5Cf_v%3D1-%5Crho%2F%5Crho_s%3D1-990%2F1570%3D1-0.63%3D0.37)
The void fraction of the bed is 0.37.
Answer:
The correct answer is Mn goes from +7 to +2.
Explanation:
The permanganate ion (Mn04-) forming by Oxygen (-2 its oxidation state) and the Mn (+7), throwing the count: +7 + (-2 x4) = -1 (the charge of the ion). Said permanganate ion is reduced in the reaction to Mn2 +.
Answer:
Mass = 2.355 g
Explanation:
Given data:
Mass of K₂O needed = ?
Mass of KNO₃ produced = 5.00 g
Solution:
Chemical equation:
K₂O + Ca(NO₃)₂ → CaO + 2KNO₃
Number of moles of KNO₃:
Number of moles = mass/molar mass
Number of moles = 5.00 g/ 101.1 g/mol
Number of moles = 0.05 mol
now we will compare the moles of KNO₃ and K₂O.
KNO₃ : K₂O
2 : 1
0.05 : 1/2×0.05 = 0.025 mol
Mass of potassium oxide needed in gram:
Mass = number of moles × molar mass
Mass = 0.025 mol × 94.2 g/mol
Mass = 2.355 g