Answer:
Solid
Liquids and gas can freely go where they want to
Answer:
Theoretical yield of C6H10 = 3.2 g.
Explanation:
Defining Theoretical yield as the quantity of product obtained from the complete conversion of the limiting reactant in a chemical reaction. It can be expressed as grams or moles.
Equation of the reaction
C6H11OH --> C6H10 + H2O
Moles of C6H11OH:
Molar mass of C6H110H = (12*6) + (1*12) + 16
= 100 g/mol
Mass of C6H10 = 3.8 g
number of moles = mass/molar mass
=3.8/100
= 0.038 mol.
Using stoichoimetry, 1 moles of C6H110H was dehydrated to form 1 mole of C6H10 and 1 mole of water.
Therefore, 0.038 moles of C6H10 was produced.
Mass of C6H10 = molar mass * number of moles
Molar mass of C6H10 = (12*6) + (1*10)
= 82 g/mol.
Mass = 82 * 0.038
= 3.116 g of C6H10.
Theoretical yield of C6H10 = 3.2 g
The answer is: "10" .
_______________________________________________________________
" A centimeter and millimeter differ from each other by a factor of "10" .
_______________________________________________________________
Note:
____________________________
100 cm = 1 m
1000 mm = 1m
____________
100 * (10) = 1000 .
_________________
The answer is: "10".
__________________________________________________________
" A centimeter and millimeter differ from each other by a factor of "10".
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Answer: -
4.25 mol of O₂ left as excess.
3.5 mol of NO₂ formed.
Explanation: -
Number of moles of NO taken = 3.5
Number of moles of O₂ taken = 6.0
The balanced chemical equation for this reaction is
2 NO+ O₂ → 2 NO₂
From the equation we can see that
2 mol of NO react with 1 mol of O₂
3.5 mol of NO react with 
x 3.5 mol NO
= 1.75 mol O₂
So Oxygen O₂ is in excess and NO is the limiting reagent.
Moles of O₂ left over = 6 - 1.75 =4.25 mol of O₂
From the balanced chemical equation we see
2 mol of NO gives 2 mol of NO₂
3.5 mol of NO gives
x 3.5 mol NO
= 3.5 mol of NO₂
First by getting moles of salicylic acid:
moles of salicylic acid = molarity * volume
= 0.02 * 0.05 L
= 0.001 mol
then moles of base KOH = molarity * volume
= 0.02 * 0.055L
= 0.0011
when total volume = 0.05 + 0.055 = 0.105 L
[salisalic acid] = moles / total volume
= 0.001 / 0.105
= 0.0095
[KOH] = moles / total volume
= 0.0011 / 0.105
= 0.01
by using H-H equation, we can get the PH:
PH = Pka + ㏒[salt/acid]
by substitution:
PH = 2.97 + ㏒[0.01 / 0.0095]
= 2.99
