The required amount of silver nitrate to produce 16.2g of silver is 25.48 grams.
<h3>What is the relation between mass & moles?</h3>
Relation between the mass and moles of any substance will be represented as:
n = W/M, where
- W = given mass
- M = molar mass
Moles of silver = 16.2g / 107.8g/mol = 0.15mol
From the stoichiometry of the given reaction it is clear that, same moles of silver nitrate is required to produce same moles of silver. So 0.15 moles of silver nitrate is required.
Mass of silver nitrate = (0.15mol)(169.87g/mol) = 25.48g
Hence required mass of silver nitrate is 25.48g.
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Answer:
In every sequence even numbers are added in order.
3, 5, 9, 15, 23, 33
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Had to look for the options and here is the answer. The concentration of glucose carriers in which the glucose concentration is being decreased to zero is 400. This level is already classified as above normal of the rate of glucose concentration. Hope this helps.