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Alchen [17]
3 years ago
6

Mary is cutting strips of paper for a craft project. Each strip is 1/6 of a sheet of paper. Mary has 2/3 of a sheet of paper lef

t to cut. She wants to determine how many more strips of paper she can cut from what is left.
Mary can cut ___ more strips than paper
Mathematics
1 answer:
nevsk [136]3 years ago
6 0

Answer:

4 more strips

Step-by-step explanation:

Given that:

Length per strip = 1/6

Fraction of paper left = 2/3

Number of strips that can be cut from the Fraction left ;

Fraction left ÷ length per strip

2/3 ÷ 1/6

2/3 * 6/ 1

(2 * 6) / (3 * 1)

12 / 3

= 4

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solniwko [45]

Answer:-91/3

Step-by-step explanation: I hope it’s right

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3 years ago
MAX POINTS
mrs_skeptik [129]

Let's do

\\ \rm\dashrightarrow y=\dfrac{3}{x-h}+k

Release k for some while

If

  • we take h=0

So

  • y=3/x

So vertical asymptote is at origin now

It mentioned that it's at x=-5 so we need to change x

  • put -5 in place of h

\\ \rm\dashrightarrow y=\dfrac{3}{x-(-5)}

\\ \rm\dashrightarrow y=\dfrac{3}{x+5}

  • Vertical asymptote at x=-5

Now

  • for k=0 horizontal asymptote at origin

But it's given

  • y is at 12

Same put y=12 in place of k

\\ \rm\dashrightarrow y=\dfrac{3}{x+5}+12

  • h=-5
  • k=12

Graph attached for verification

3 0
2 years ago
I'm behind on hw and I'm going to fail if I don't get help.
Reil [10]
Number two is A........hope this helps
6 0
3 years ago
Will give BRAINLIEST!!!
forsale [732]

Answer:

y = 2x - 5

Step-by-step explanation:

3 0
3 years ago
Write in simplest form:<br> <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24a%5E%7B10%7Db%5E%7B6%7D%7D" id="TexFormula1" ti
Charra [1.4K]

Answer:

2a^3b^2\sqrt[3]{3a}

Step-by-step explanation:

Use the following rules for exponents:

a^m*a^n=a^{m+n}\\\\\sqrt[3]{x^3}=x

Simplify 24. Find two factors of 24, one of which should be a perfect cube:

8*3=24\\\\2^3=8

Insert:

\sqrt[3]{2^3*3a^{10}b^6}

Now split the exponents. Split 10 into as many 3's as possible:

10=3+3+3+1

Insert as exponents:

\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^6}

Split 6 into as many 3's as possible:

6=3+3

Insert as exponents:

\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^3*b^3}

Now simplify. Any terms with an exponent of 3 will be moved out of the radical (rule #2):

2\sqrt[3]{3*a^3*a^3*a^3*a^1*b^3*b^3}\\\\\\2*a*a*a\sqrt[3]{3*a^1*b^3*b^3}\\\\\\2*a*a*a*b*b\sqrt[3]{3*a^1}

Simplify:

2a^3b^2\sqrt[3]{3a}

:Done

6 0
3 years ago
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